Check if array element has certain format

Question

I have an array with elements. These elements are object paths. Some are just one level deep : ui.main and some are multiple levels deep : ui.main.tab. Now my intention is to perform an action whenever the path is just one level deep.

so for example ui.main => perform action. ui.tab.main => do nothing etc.

I know i have to use some sort of loop and a regular expression, but i am having trouble combining the two as i am not comfortable working with those.

By elements, do you mean strings? ['foo.bar', 'foo.bar.baz']? — CertainPerformance
– CertainPerformance, Commented Aug 9, 2019 at 7:56
Yes sorry, the elements are basically strings as in your example @CertainPerformance — Kevin.a
– Kevin.a, Commented Aug 9, 2019 at 7:57

Andy · Accepted Answer · 2019-08-09 08:06:36Z

2

You could split the string on the . and check the length:

const arr = ['ui.main.tab', 'ui.main', 'test.main', 'test.main.tab'];

arr.forEach(el => {
  if (el.split('.').length === 2) console.log(el);
});

answered Aug 9, 2019 at 8:06

Andy

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CertainPerformance · Accepted Answer · 2019-08-09 07:59:07Z

2

I'd check whether the indexOf a . is the same as the lastIndexOf a . (and is not -1), fulfilling the condition when there's exactly one . in the string being checked:

const arr = ['ui.main', 'ui.tab.main'];
arr.forEach((str) => {
  const index = str.indexOf('.');
  if (index !== -1 && str.lastIndexOf('.') === index) {
    console.log('doing something', str);
  }
});

answered Aug 9, 2019 at 7:59

CertainPerformance

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Comments

Alejandro Montilla · Accepted Answer · 2019-08-09 08:07:29Z

1

const arr = ['ui.main', 'ui.tab.main', 'ui.foo'];

arr.forEach((str) => {
  const count = (str.match(/\./g) || []).length;
  if (count === 1) {
	console.log("do something with: " + str);
  }
});

answered Aug 9, 2019 at 8:07

Alejandro Montilla

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