php | Simple question on conditional statement

Question

I'm new to php and I would like to have a conditional statement like this:

if ($foo != 'Any') { $condition .= '$this_foo == $foo &&';}
if ($bar != 'Any') { $condition .= '$this_bar == $bar &&';}
if ($txt != 'Any') { $condition .= '$this_txt == $txt &&';}
$condition .= '$num1 > 0 && $num2 < 1000';

if (...[php would parse the $condition variable])
{
  someoperations
}

What is the proper syntax for the if statement to parse the variable $condition? So the conditional statement depends on the other variables and to prevent a long nested conditional statement.

Thanks in advance!

dee-see · Accepted Answer · 2011-04-28 01:03:34Z

2

Well it's not exactly parsing, but you could evaluate your condition as the code is executed.

$condition = true;
if ($foo != 'Any') { $condition = $condition && ($this_foo == $foo);}
if ($bar != 'Any') { $condition = $condition && ($this_bar == $bar);}
if ($txt != 'Any') { $condition = $condition && ($this_txt == $txt);}
$condition = $condition && ($num1 > 0 && $num2 < 1000);

if ($condition)
{
  someoperations
}

So let's say that $foo != 'Any' is true, that would result in

$condition = true && ($this_foo == $foo) && ($num1 > 0 && $num2 < 1000);

Let's pretend $this_foo == $foo, $num1 == 45 and $num2 == 2300

$condition = true && true && (true && false);
$condition = false;

and your if won't execute.

edited Apr 28, 2011 at 1:03

answered Apr 28, 2011 at 0:58

dee-see

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2 Comments

iamebet Over a year ago

thanks for this! it helped me. I'll upvote this when I have the reputation.

iamebet Over a year ago

there we go. I only joined here yesterday so I'm a newbie. =)

Myles · Accepted Answer · 2011-04-28 00:57:53Z

0

I believe what you want is

if (eval("return " . $condition)) {...}

Making sure to check for the FALSE case if the parsing fails.

answered Apr 28, 2011 at 0:57

Myles

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