Selenium - Find all elements and use WebDriverWait with for loop

Question

I have some problems with Selenium where I am trying to find all elements and then try to use WebDriverWait:

WebDriverWait(browser, 5).until(
    EC.presence_of_element_located((By.XPATH,
                                    "//*[contains(text(), 'Hello')]")))
getAllErrors = WebDriverWait(browser, 5).until(
    EC.presence_of_all_elements_located((By.CLASS_NAME, "message")))

for productErrors in getAllErrors:

    if 'Sad moments' in productErrors.text:

        totalProduct = WebDriverWait(browser, 5).until(
            EC.presence_of_element_located((productErrors.find_element_by_xpath("//input[@type='number']"))))

        #How to call productErrors and to use WebDriverWait with it?

I wonder how to use the for loop data and use WebDriverWait with the for loop varaiable?

Basically something like

for productErrors in getAllErrors:

    WebDriverWait(browser, 5).until(EC.presence_of_element_located((productErrors.find_element_by_xpath("//input[@type='number']")))) 
    #Use productErrors For loop and find the xpath from productErrors

Guy · Accepted Answer · 2019-11-26 12:49:17Z

3

There is no presence_of for already located element, but you can use visibility_of

wait = WebDriverWait(browser, 5)
for productErrors in getAllErrors:
    wait.until(EC.visibility_of(productErrors.find_element_by_xpath("./following-sibling::div//input[@type='number']")))

Don't forget to add . to the xpath for context search. You can also declare WebDriverWait(browser, 5) one time and use it everywhere.

edited Nov 26, 2019 at 12:49

answered Nov 26, 2019 at 11:04

Guy

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8 Comments

Murthi Over a year ago

You can use presence_of_element_located here as well.

Guy Over a year ago

@Murthi presence_of_element_located receive By as parameter, not WebElement.

Thrillofit86 Over a year ago

Is it possible to do wait = WebDriverWait(productErrors, 5) instead of browser?

Guy Over a year ago

@Thrillofit86 No, WebDriverWait __init__ expects WebDriver. Why? what are trying to do by doing that?

Guy Over a year ago

Let us continue this discussion in chat.

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