can you help me get output like this by using bellow data:
name='suraj,rohit,rahul'
score='34,45,55'
I want to make a list like this:
[['suraj', 34], ['rohit', 45], ['rahul', 55]]
Please help.
Add a comment
|
5 Answers
You can use:
list(zip(name.split(','), score.split(',')))
[('suraj', '34'), ('rohit', '45'), ('rahul', '55')]
EDIT
People wanted lists instead ot tuples and int instead of strings, here we go:
[[x, int(y)] for x, y in zip(name.split(','), score.split(','))]
[['suraj', 34], ['rohit', 45], ['rahul', 55]]
You can use list comprehension.
[[i,int(j)] for i,j in zip(name.split(','), score.split(','))]
#[['suraj', 34], ['rohit', 45], ['rahul', 55]]
Comments
Instead of using a list, you can use a dictionary in order to make it more efficient while making it work properly at the same time. Please refer to the following code I have provided below in order to make your program much more better. code:
name=""
score=""
Dictionary={"suraj,":34,"rohit,":45,"rahul":55}
for A,B in Dictionary.items():
name=name+A
score=score+str(B)+","
print(name)
print(score)
I hope this cleared your doubt
Comments
you can combine map() and zip() functions to get list of list,also to conver list of sting into list of integers:
name='suraj,rohit,rahul'
score='34,45,55'
print (list(map(list, zip(name.split(','), map(int,score.split(','))))))
output:
[['suraj', 34], ['rohit', 45], ['rahul', 55]]
you can also use basic for loop:
name='suraj,rohit,rahul'.split(',') # get list of names
score='34,45,55'.split(',') # get list of scores
result = []
for i in range(len(name)):
result.append([name[i],int(score[i])])
print (result)
output:
[['suraj', 34], ['rohit', 45], ['rahul', 55]]
Comments
You can use a lambda function instead:
print(list(map(lambda x,y: [x,y], name.split(','), score.split(','))))
