Image rotation in JavaScript using array

Question

I am writing an image rotation functionality. I have created an array to store degrees for transform function.

However I need to know instead of increment array, to move next and previous between the rotations array.

Switching from left and right doesn't work as expected.

https://jsfiddle.net/andreas20/v94zLg8b/

rotations = ['90deg', '180deg', '270deg', '360deg']
let img = document.getElementById('img_blob');
let array_increment = 0

$('#left').click(() => {
  if (array_increment > 3)
    array_increment = 0

  img.style.transform = 'rotate(-' + rotations[array_increment] + ')'
  array_increment++
  console.log(array_increment)
})

$('#right').click(() => {
  if (array_increment > 3)
    array_increment = 0

  img.style.transform = 'rotate(' + rotations[array_increment] + ')'
  array_increment++
  console.log(array_increment)
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button id="left">Left</button>
<button id="right">Right</button><br>

<img id="img_blob" src="https://i.imgur.com/vgD5ycf.jpg">

Andy · Accepted Answer · 2020-03-13 09:28:33Z

3

you could do rotation something like that without using array

let img = document.getElementById('img_blob');
let rotationValue = 0;

$('#left').click(() => rotate(-1));
$('#right').click(() => rotate(1));

function rotate(direction) {
  rotationValue += 90 * direction;
  rotationValue = rotationValue % 360;
  img.style.transform = `rotate(${rotationValue}deg)`;
  // console.log(rotationValue);
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="img_blob" src="https://dummyimage.com/150x150/000/fff" />
<button id="left">Left</button>
<button id="right">Right</button>

edited Mar 13, 2020 at 9:28

Andy

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answered Mar 13, 2020 at 9:18

Oleg Bondarenko

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1 Comment

user12510360 Over a year ago

great solution.

yunzen · Accepted Answer · 2020-03-13 09:24:06Z

You had a misconception with the minus in the rotation

-90deg, -180deg, -270deg, -360deg is not the same as 90deg, 180deg, 270deg, 360deg backwards (that would be 0deg, -90deg, -180deg, -270deg, so with an offset of one)

What I do is, I start at zero and move inside the array backwards and forwards

rotations = ['0deg', '45deg', '90deg', '135deg', '180deg', '225deg', '270deg', '315deg']
let img = document.getElementById('img_blob');
let array_increment = 0

array_increment = 0;
$('#left').click(() => {
  array_increment--
  array_increment = (array_increment + rotations.length) % rotations.length
  console.log(array_increment)

  img.style.transform = 'rotate(' + rotations[array_increment] + ')'
})

$('#right').click(() => {
  array_increment++
  array_increment = (array_increment + rotations.length) % rotations.length
  console.log(array_increment)

  img.style.transform = 'rotate(' + rotations[array_increment] + ')'
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button id="left">Left</button>
<button id="right">Right</button><br>

<img id="img_blob" src="https://i.picsum.photos/id/190/300/300.jpg">

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Image rotation in JavaScript using array

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Image rotation in JavaScript using array

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