I would ike to make a string with digits like this: 123456789.
I can write this easily with a for loop.
x = ""
for i in range(1, 10):
x += str(i)
However, I would like to write this with no explicit for loops.
Are there any creative ways, to do this?
Just for the sake of it, you could use a recursive function if you really wanted:
def stringer(n):
if n <= 1:
return '1'
return stringer(n-1) + str(n)
What the function does is return the string 123...n by calling itself recursively, decreasing n each time until reaching 1, and then building the string on the way back.
If called as print(stringer(9)) this will give:
123456789
No loops there, just a nice call stack
You could create the range as follows:
rangeToConvert = range(1, 10)
And than join the list to create a string. Only issue is that the values in the rangeToConvert are ints so you need to convert them to string in order to use the join function.
x = ''.join(map(str, rangeToConvert))
X would be in this case:
'123456789'
Should you wish to use the itertools module of python you could do something like this:
from itertools import takewhile, count
x = ''
x = ''.join(map(str, takewhile(lambda x: x < 10, count(1))))
print(x)
When the above code snippet runs, it prints:
123456789
x = '123456789'will be some kind of a loop, even if not an explicit one that you can see