Indexing a string,getting SyntaxError/Python

Question

So when I do something like this :

    x=str(19072000)
    day=x[:2]
    month=x[2:4]
    year=x[4:]
    final=day+"/"+month+"/"+year
    print(final)
I get:19/07/2000

>>>x=str(01011930)
File"(Stdin)",line 1
x=str(01011930)
                       ^
SyntaxError:invalid token

But when i try to do the same thing but with 01011930 i get SyntaxError:invalid token,any ideas why?

Tom Karzes · Accepted Answer · 2020-05-07 14:32:55Z

1

The problem is the leading 0 in your integer constant.

In Python 2, an integer that begins with a 0 is taken to be an octal constant, which doesn't allow the digits 8 or 9 (and even without them, the resulting number will be quite different from what you intend).

In Python 3, it isn't allowed at all, except for 0 itself. (Octal constants begin with 0o in Python 3, similar to how hex constants begin with 0x.)

To do what you want, just remove the leading zero. Then you can zero-pad using:

x = "%08d" % 1011930

This will set x to the string '01011930'. Then your indexing will work.

Equivalently, you can use:

x = "{:08d}".format(1011930)

edited May 7, 2020 at 14:32

answered May 7, 2020 at 14:27

Tom Karzes

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2 Comments

Juke Over a year ago

When i try to run the code with your solution in command line it works,however when i try to do it in the eclipse it still gives me:

r1=Radnik("Petar","Petrovic",1907000820015,01011930 ,"Senta","Srbija")                                                                                        ^ SyntaxError: invalid token

I have a class written for this,it works with any other date/numbers but with anything that starts with 0 it still won't work.

Tom Karzes Over a year ago

You didn't remove the leading zero, it's still there: 01011930. You need to remove the leading zeros from all of your integer constants. Change it to 1011930. The leading zeros are causing your syntax errors.

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