typescript concat warning no overloading match

Question

console.log([].concat(0, 123))

I've no clue what the error means

No overload matches this call.
  Overload 1 of 2, '(...items: ConcatArray<never>[]): never[]', gave the following error.
    Argument of type '0' is not assignable to parameter of type 'ConcatArray<never>'.
  Overload 2 of 2, '(...items: ConcatArray<never>[]): never[]', gave the following error.
    Argument of type '0' is not assignable to parameter of type 'ConcatArray<never>'.ts(2769)

I assign to a variable and declare any type I still see the error.

This console.log(([] as number[]).concat(0, 123)) works. Check: stackoverflow.com/a/54117175 for further information. — Yoshi
– Yoshi, Commented May 14, 2020 at 8:21

DevLoverUmar · Accepted Answer · 2020-05-14 08:26:02Z

1

Try this:

console.log(([] as any[]).concat(0, 123));

For more info, check this github issue

edited May 14, 2020 at 8:26

answered May 14, 2020 at 8:16

DevLoverUmar

14.3k16 gold badges80 silver badges113 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

typescript concat warning no overloading match

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related