3

I have a CSV file delimited by a single space character, like so-

<HEADING ROW>
a b c,d,e,f
m n o,p,q

Here, the last element is a list of strings concatenated with the comma separator. I'm currently using the OpenCsv library to parse this CSV file into a list of POJOs.

Here is my POJO definition:

import com.opencsv.bean.CsvBindByName;

import java.util.List;

public class Foo {

    @CsvBindByName(column = "heading1", required = true)
    private Long first;

    @CsvBindByName(column = "heading2", required = true)
    private String third;

    @CsvBindByName(column = "heading3", required = true)
    private List<String> fourth;
}

So all the fields in this object are of different types, especially the last one, which is of a list type, and can be of any non-zero length. Here's my code to map the CSV file to a list of these objects:

    public List<Foo> readCsvFromPath(final String filePath) throws IOException {
        try (Reader reader = Files.newBufferedReader(Paths.get(filePath));) {
            CsvToBean<Foo> csvToBean = new CsvToBeanBuilder<Foo>(reader)
                    .withSeparator(' ')
                    .withType(Foo.class)
                    .build();
            return csvToBean.parse();
        }
    }

What I'm not sure about here is how can the last element of the CSV file, ie, "c,d,e,f" or "o,p,q" will get respectively mapped to lists like {"c", "d", "e", "f"} and {"o", "p", "q"}?

1 Answer 1

5

You can use @CsvBindAndSplitByName.

Replace this code

@CsvBindByName(column = "heading3", required = true)
private List<String> fourth;

with

@CsvBindAndSplitByName(column = "heading3", required = true, elementType = String.class, splitOn = ",")
private List<String> fourth;
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