Segmentation fault when using struct in C

Question

Why do I get Segmentation fault here? I'm very new to C and it's really hard for me. I googled much and found out that it have to be working normally.

#include <stdio.h>

struct school
{
    int schoolNum;
    int year;
    int gradNum;
    int univNum;
};

int main()
{
    struct school schools[5] = {
        114, 2020, 470, 300,
        86, 2019, 545, 450,
        231, 2020, 340, 320,
        113, 2020, 435, 395,
        55, 2019, 395, 380
    };

    printf('%d\n', schools[0].gradNum);

    return 0;
}

The single quotes in your printf call are wrong. use double quotes for your format string. You should get a compiler warnings about the problem. (Enable all warnings.) — Bodo
– Bodo, Commented Jul 31, 2020 at 12:42
You may also like to add 4 pairs of braces { ... } in your initializer array of structures. — Adrian Mole
– Adrian Mole, Commented Jul 31, 2020 at 12:46
A decent compiler should emit a warning about multi.character literals, and if not then you need to enable more warnings. — Some programmer dude
– Some programmer dude, Commented Jul 31, 2020 at 12:47

e2r3p13 · Accepted Answer · 2020-07-31 12:58:22Z

3

There's two errors in your code, as said in the comments, you need to replace single quotes by double quotes in your printf call. Then you need to add braces pairs to enclose each school instance, as below:

struct school schools[5] = {
        {114, 2020, 470, 300},
        {86, 2019, 545, 450},
        {231, 2020, 340, 320},
        {113, 2020, 435, 395},
        {55, 2019, 395, 380}
    };

answered Jul 31, 2020 at 12:58

e2r3p13

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1 Comment

M. Nejat Aydin Over a year ago

In fact, omitting the inner braces is not an error per se, but adding them highly recommended for readability.

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