regex c# string

Question

I would like to transform this claim that I get "[\" 75 \ ", \" 91 \ "]" to (75,91)

I used regex.split but I don't know how to do it.

if (Zone != null)
{
    filtrer.Append(" and depalcement in (");

    foreach (string i in Zone)
    {
        var diviser=Regex.Split(i, @"\");
        filtrer.Append(diviser);
    }
}

Is your input actually JSON? Then you´re better off using JsonConvert than trying to parse this yourself. — MakePeaceGreatAgain
– MakePeaceGreatAgain, Commented May 10, 2021 at 10:37
You are not trying to build up an SQL statement here, are you? — Fildor
– Fildor, Commented May 10, 2021 at 10:57
Stack Overflow is english-only. Please try and stick to it, thanks. @KOMARA ( SO est en anglais uniquement. Si vous le pouvez, veuillez vous en tenir à l'anglais. ) — Fildor
– Fildor, Commented May 10, 2021 at 11:53

Oliver · Accepted Answer · 2021-05-10 11:23:12Z

2

No Regex, just JSON. Try this:

var content = "[\"75\",\"91\"]";
var list = System.Text.Json.JsonSerializer.Deserialize<List<string>>(content);
    
var numbers = list.Select(int.Parse);
    
foreach(var number in numbers)
{
    Console.WriteLine(number);
}

answered May 10, 2021 at 11:23

Oliver

45.4k8 gold badges101 silver badges165 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

tmaj · Accepted Answer · 2021-05-10 12:49:59Z

1

For completeness; to get from "[\" 75 \", \" 91 \"]" to (75,91) using regex the code could be something like this:

var s2 = "(" + Regex.Replace(input: s, pattern: "[^0-9,]", "") + ")"; // or @"[^\d,]"

Pattern:

[...] - character set aka character class aka 'any of'
^ - negate
0-9 or \d - digit
, comma
together it's any character that isn't a digit or a comma

answered May 10, 2021 at 12:49

tmaj

35.9k12 gold badges108 silver badges143 bronze badges

Collectives™ on Stack Overflow

regex c# string

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related