How can I detect integer overflow in integer multiplication

Question

int base, power, result = 1;   
for (int i = 1; i <= power; i++) {
    result *= base;
}
System.out.println(base + " to the power of " + power + " result: " + result);

10 to the power of 9 result: 1000000000 but;
10 to the power of 10 result: 1410065408

In my application this is logically an error but how can I detect this error before the println? for instance, when this error occurs, I want to print "result data type is int 32bit, it must not exceed 2,147,483,647"

How can I catch these kinds of errors?

President James K. Polk · Accepted Answer · 2021-07-27 00:19:16Z

1

https://www.baeldung.com/java-overflow-underflow I have found an enough answer here. I have corrected my code like this:

try {
    for (int i = 1; i <= power; i++) {
        result = Math.multiplyExact(base, result);
    }
} catch(ArithmeticException intSize) {
    base = result = 0;
    System.out.println("out of size int32: ")
}

edited Jul 27, 2021 at 0:19

President James K. Polk

42.3k34 gold badges113 silver badges149 bronze badges

answered Jul 26, 2021 at 21:03

Hakan ÖZHAN

214 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How can I detect integer overflow in integer multiplication

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related