Comparing two arrays of nested objects and return new array of objects if compared values are not the same in javascript

Question

I have been having trouble trying to figure out how to get this to work. I have two arrays of nested objects arr1 and arr2.

let arr1 =[{
        id: 1,
        rideS: [
        {
          id: 12,
          station: {
            id: 23,
            street: "ABC"
          }
        }
      ]
},
  {
    id: 2,
        rideS: [
        {
          id: 13,
          station: {
            id: 24,
            street: "MMM"
          }
        }
      ]
  }
 ]
 
let arr2 = [
      {
        id: 1,
        so: {
          id: 33,
          sos: [{
            id: 44,
            station: {
              id: 55,
              street: "ABC"
            }
          },
          {
            id: 74,
            station: {
              id: 11,
              street: "DDD"
            }
          }
            
            ]
        }
      },
        {
        id: 2,
        so: {
          id: 34,
          sos: [{
            id: 45,
            station: {
              id: 56,
              street: "RRR"
            }
          },
            {
            id: 51,
            station: {
              id: 66,
              street: "ZZZ"
            }
          }
            ]
        }
      },
    {
        id: 3,
        so: {
          id: 35,
          sos: [{
            id: 46,
            station: {
              id: 57,
              street: "MMM"
            }
          },
            {
            id: 75,
            station: {
              id: 66,
              street: "VVV"
            }
          }
            
            ]
        }
      }
   ]

I need to compare arr2 with arr1 using "street" porperty value of first object array in "sos" and as result i need to return not matched objects

For example if i compare this two arrys as result i expect:

let result = [ 
 {
        id: 2,
        so: {
          id: 34,
          sos: [{
            id: 45,
            station: {
              id: 56,
              street: "RRR"
            }
          },
            {
            id: 51,
            station: {
              id: 66,
              street: "ZZZ"
            }
          }
            ]
        }
      }
]

and this is what i have tried to do

let result = arr2.filter(o1 => o1.so.sos.some(o2 => !arr1.some(a1=> a1.rideS.some(a2 => o2.station.street === a2.station.street))))

and as result i get all objects, but i need somthing like this prob:

 let result = arr2.filter(o1 => o1.so.sos[0].some(o2 => !arr1.some(a1=> a1.rideS.some(a2 => o2.station.street === a2.station.street))))

are you saying if even one of the street name that is preset in Arr1 is matching Arr2, irrespective of any other property it should be removed? — vaira
– vaira, Commented Sep 7, 2021 at 15:26
Yes sir, if any street name from arr1 have same name as street property in arr2 (but only comparing with first object of array "sos") sould not be returned in results — Stefan Simić
– Stefan Simić, Commented Sep 7, 2021 at 15:44

vaira · Accepted Answer · 2021-09-07 15:38:51Z

First we need to take out all the street address in a dictionary named streetDic and then check in array two if no value inside streetDic is present in its streets.

let arr1 =[{
    id: 1,
    rideS: [
    {
      id: 12,
      station: {
        id: 23,
        street: "ABC"
      }
    }
  ]
},
{
id: 2,
    rideS: [
    {
      id: 13,
      station: {
        id: 24,
        street: "MMM"
      }
    }
  ]
}
]

let arr2 = [
  {
    id: 1,
    so: {
      id: 33,
      sos: [{
        id: 44,
        station: {
          id: 55,
          street: "ABC"
        }
      },
      {
        id: 74,
        station: {
          id: 11,
          street: "DDD"
        }
      }
        
        ]
    }
  },
    {
    id: 2,
    so: {
      id: 34,
      sos: [{
        id: 45,
        station: {
          id: 56,
          street: "RRR"
        }
      },
        {
        id: 51,
        station: {
          id: 66,
          street: "ZZZ"
        }
      }
        ]
    }
  },
{
    id: 3,
    so: {
      id: 35,
      sos: [{
        id: 46,
        station: {
          id: 57,
          street: "MMM"
        }
      },
        {
        id: 75,
        station: {
          id: 66,
          street: "VVV"
        }
      }
        
        ]
    }
  }
]



let streetDic = arr1.reduce((dic, o) => {   o.rideS.forEach(r => dic[r.station.street] = true); return dic; } , {})

let result = arr2.filter(o => !o.so.sos.some(s => streetDic[s.station.street]))

console.log(result);

Nikola Pavicevic · Accepted Answer · 2021-09-07 15:40:10Z

1

Try to replace some with every:

let arr1 = [
  { id: 1, rideS: [{id: 12, station: {id: 23, street: "ABC",},},],},
  { id: 2, rideS: [{id: 13, station: {id: 24, street: "MMM",},},],},
];

let arr2 = [
  {id: 1, so: {id: 33, sos: [{id: 44,station: {id: 55,street: "ABC",},}, {id: 74, station: {id: 11, street: "DDD",},},],},},
  {id: 2, so: {id: 34,sos: [{id: 45, station: {id: 56, street: "RRR",},},{id: 51, station: {id: 66, street: "ZZZ",},},],},},
  {id: 3, so: {id: 35, sos: [{id: 46, station: {id: 57, street: "MMM",},},{id: 75, station: {id: 66, street: "VVV",},},],},},
];
    
let result = arr2.filter(o1 => o1.so.sos.every(o2 => !arr1.some(a1 => a1.rideS.some(a2 => o2.station.street === a2.station.street))))
console.log(result)

answered Sep 7, 2021 at 15:40

Nikola Pavicevic

23.6k9 gold badges30 silver badges52 bronze badges

1 Comment

Nikola Pavicevic Over a year ago

Don't thank me, it was your code, I just spotted your lapsus :) cheers mate :),

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