Error with explode and in_array in php

Question

I would like to check the following condition with php

$string = '10-15~15-20~20-25~';

    $stringArray = explode('~',rtrim($string,'~'));

    if (in_array('20-25', $stringArray)) {
       echo 'Found';
    }
    else
    {
        echo 'Not found';
    }

20-25 is present in my array but, it always shows not found

Berro · Accepted Answer · 2011-08-09 08:30:59Z

1

There are some errors in your code. Here is a corrected version.

$string = '10-15~15-20~20-25~';
$stringArray = explode('~',rtrim($string,'~')); // corrected here, missing "$" before "string"
if (in_array('20-25', $stringArray)) { // corrected here, wrong variable name "priceArray"
   echo 'Found';
}
else
{
    echo 'Not found';
}

answered Aug 9, 2011 at 8:30

Berro

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Comments

J0HN · Accepted Answer · 2011-08-09 08:27:18Z

0

replace $priceArray with $stringArray. It's just a typo. You are searching "20-25" in non-initialized variable.

answered Aug 9, 2011 at 8:27

J0HN

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