gdb: Defining a function with multiple arguments using if...else

Question

How can I define a gdb convenience function with optional args? I've tried below, which doesn't work:

(gdb) define v
Type commands for definition of "v".
End with a line saying just "end".
>if $argc == 1
 >echo 1
 >else if $argc == 2
 >echo 2
 >else
 >echo neither
 >end
>end
(gdb) v
neither(gdb) v 1
1Undefined command: "else".  Try "help".
(gdb) v 2
1Undefined command: "else".  Try "help".

Employed Russian · Accepted Answer · 2022-01-10 22:01:20Z

1

I've tried below, which doesn't work:

It doesn't work because there is no else in the GDB scripting language.

You can work around this with:

define v
  if $argc == 1
    echo 1
  end
  if $argc == 2
    echo 2
  end
  if $argc < 1 || 2 < $argc 
    echo neither
  end
end

but you'll probably get better results by deferring to the embedded Python.

answered Jan 10, 2022 at 22:01

Employed Russian

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1 Comment

x-yuri Over a year ago

From what I can see, there is else, but no else if.

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