Split String to get an Array

Question

In Database :- "["http://localhost//image/aeefb050911334869a7a5d9e4d0e1689.jpg","http://localhost//image/959776b99b006e5785c3a3364949ce47.jpg"]"

After Json_decode = ["http://localhost//image/aeefb050911334869a7a5d9e4d0e1689.jpg","http://localhost//image/959776b99b006e5785c3a3364949ce47.jpg"]

Output i Want:- [0] - http://localhost//image/aeefb050911334869a7a5d9e4d0e1689.jpg [1] - http://localhost//image/959776b99b006e5785c3a3364949ce47.jpg

Code:-

   @if(is_array(json_decode($data->item_image)))
                                    @php $image = json_decode($data->item_image);
                                    @endphp
                                            @foreach($image as $key=>$row)
                                                @if($key == 0)
                                                <div class='carousel-item active'>
                                                    <!-- <img class='img-size img-responsive' src="{{ asset('image/'. $row) }}" /> -->
                                                    <img class='img-size img-responsive' src="{{ $row }}" />
                                                </div>
                                                @else
                                                <div class='carousel-item'>
                                                    <!-- <img class='img-size' src="{{ asset('image/'. $row) }}" /> -->
                                                    <img class='img-size' src="{{ $row }}" />
                                                </div>
                                                @endif
                                            @endforeach
                                    @else

                                    @endif

I'm kinda confused, looks like you're already getting an array of Strings? You could break apart the string by doing stringName.split(","). For ex: String longString = "zyzabcstring.jpg,string2.jpg,string3.jpg"; String[] strings = longString.split(","); — dilbert2219
– dilbert2219, Commented Feb 1, 2022 at 6:30

Reza ghz · Accepted Answer · 2022-02-01 07:01:08Z

2

you can use this

$str = '["http://localhost//image/aeefb050911334869a7a5d9e4d0e1689.jpg",
"http://localhost//image/959776b99b006e5785c3a3364949ce47.jpg"]';
eval("\$myarray = $str;");
print_r($myarray);

answered Feb 1, 2022 at 7:01

Reza ghz

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2 Comments

Nikhil Shukla Over a year ago

Thank You Sir Now it's Working Thanks a lot... !!

Gert B. Over a year ago

Why with eval()? eval should never be used if there is another solution.

Nikhil Shukla · Accepted Answer · 2022-02-01 07:12:50Z

1

 @if(json_decode($data->item_image) != '')
                                    @php $image = json_decode($data->item_image);
                                            eval("\$myarray = $image;");
                                    @endphp
                                            @foreach($myarray as $key=>$row)
                                                @if($key == 0)
                                                <div class='carousel-item active'>
                                                    <!-- <img class='img-size img-responsive' src="{{ asset('image/'. $row) }}" /> -->
                                                    <img class='img-size img-responsive' src="{{ $row }}" />
                                                </div>
                                                @else
                                                <div class='carousel-item'>
                                                    <!-- <img class='img-size' src="{{ asset('image/'. $row) }}" /> -->
                                                    <img class='img-size' src="{{ $row }}" />
                                                </div>
                                                @endif
                                            @endforeach
                                    @else

                                    @endif

answered Feb 1, 2022 at 7:12

Nikhil Shukla

311 silver badge11 bronze badges

7 Comments

Gert B. Over a year ago

99,99% of the time eval() is not needed to solve a problem. In this case it is not needed, so don't use it.

Nikhil Shukla Over a year ago

Can you suggest an alternative for eval() in this case ?

Gert B. Over a year ago

Json decode comes with a second parameter "associative", so json_decode($data->item_image, true) might give the array. If that doen't work, you can explode the string. I personally never needed to use eval() because there was always another (so better) way.

Nikhil Shukla Over a year ago

@GertB After Exploding it'll give output like Array = ( [0] => ["localhost//image/aeefb050911334869a7a5d9e4d0e1689.jpg" [1] => "localhost//image/959776b99b006e5785c3a3364949ce47.jpg"] )But this is Not i want

Gert B. Over a year ago

Well, what if I would add php code in the database column, eval() will run it. thats a big security risk.

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