in html <select>, php code to add <option>s

Question

I would like to add the years 2011-2001 in my drop-down-box (2012-2002 in next year, etc...).

Since I don't want to change my code I thought to do it in php.

I had it like this which worked:

<select name="purchaseYear" size="1">
   <?echo "<option>" . date("Y") . "</option>";?>
   <?echo "<option>" . date("Y") - 1 . "</option>";?>
   ...
</select>

Now I want to realise it with a for-loop and tried it like this:

<select name="purchaseYear" size="1">
    <?
    for ($i = 0; $i <= 9; $i++) {
       echo "<option>" . date("Y") - $i . "</option>";
    }
    ?>
</select>

Which gave me an empty drop-down-box.

What do I need to change? And why didn't it work?

What does the HTML output look like?

Dennis
– Dennis

2011-08-31 13:51:53 +00:00
Commented Aug 31, 2011 at 13:51 — Dennis
– Dennis, Commented Aug 31, 2011 at 13:51

pb149 · Accepted Answer · 2011-08-31 13:59:16Z

6

Try this:

<select name="purchaseYear" size="1">

<?php for ($i = 0; $i <= 9; $i++)
{
    $date = date("Y") - $i;
    echo "<option value='$date'>" . $date . "</option>";
}


?>

Just so you know: the issue was with Operator Precedence. You could also add parenthesis like this to solve the problem:

<select name="purchaseYear" size="1">

<?php for ($i = 0; $i <= 9; $i++)
{
    echo "<option>" . (date("Y") - $i) . "</option>";
}


?>

edited Aug 31, 2011 at 13:59

answered Aug 31, 2011 at 13:53

pb149

2,2981 gold badge22 silver badges30 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Pratik · Accepted Answer · 2011-08-31 13:54:47Z

2

try this way

<select name="purchaseYear" size="1">
<? for ($i = 0; $i <= 9; $i++)
    {
      echo "<option>" . (date("Y") - $i) . "</option>";
    }?>

because you do the arithmetic operation with concatenating with the string that why you have to put arithmetic operation into the () bracket

or you can first store the year in any another variable and the pass that variable into this echo statement

answered Aug 31, 2011 at 13:54

Pratik

30.9k19 gold badges88 silver badges164 bronze badges

Comments

Kazz · Accepted Answer · 2011-08-31 13:56:03Z

0

<select name="purchaseYear" size="1">   
    <?php
    for ($i = 0; $i <= 9; $i++)
    {
        ?>
        <option><?= date("Y") - $i ?></option>
        <?php
    }
    ?>
</select>

This worked for me!

I try to avoid putting HTML into echo statements if I can help it.

answered Aug 31, 2011 at 13:56

Kazz

1001 gold badge2 silver badges5 bronze badges

Comments

Nev Stokes · Accepted Answer · 2011-08-31 14:04:00Z

0

Or you can scrap the calculation in the loop body and perform it during setup:

<select name="purchaseYear" size="1">
<?php
    for ($i = date('Y'), $j = ($i - 10); $i >= $j; $i--) {
        echo '<option>', $i, '</option>', PHP_EOL;
    }
?>
</select>

answered Aug 31, 2011 at 14:04

Nev Stokes

9,9475 gold badges46 silver badges46 bronze badges

Comments

Lightness Races in Orbit · Accepted Answer · 2011-08-31 14:28:33Z

-1

This:

echo "<option>" . date("Y") - $i . "</option>";

becomes this:

echo "<option>" . (date("Y") - $i) . "</option>";

answered Aug 31, 2011 at 14:28

Lightness Races in Orbit

387k77 gold badges672 silver badges1.1k bronze badges

Collectives™ on Stack Overflow

in html <select>, php code to add <option>s

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related