Rails / jQuery AJAX not succeeding

Question

I have a Rails application where I have some ajax calls, it usally works just fine, but this one I can get working:

I tried running the rails class from the browser, works fine, and I tried calling an alert with the params just before the ajax call, works fine.. but no connection, whats wrong?

jQuery:

   $.ajax({
  url: "things/ajax_text_read",
  data: "book_id=" + book_id  + "&page_number=" + page_number  + "&type="+ type,
  success: function(){$(this).text('data'); }
});

Rails:

    def ajax_text_read
@book_id = params['book_id']
@page_number = params['page_number']  
@type = params['type']

@text = Thing.where(:parent_id => @page_number, :book => @book_id, :media_type => 'text')  

if(@type=='description')
render :inline => "<%= @text[0].description %>" 
else
render :inline => "<%= @text[0].title %>" 
end

end

yoda · Accepted Answer · 2011-09-07 20:41:31Z

1

Supposing that things/ajax_text_read is a valid uri :

$.ajax({
  url: "things/ajax_text_read",
  data: "book_id=" + book_id  + "&page_number=" + page_number  + "&type="+ type,
  success: $.proxy(function(data){
      $(this).text(data);
  }, this)
});

edited Sep 7, 2011 at 20:41

answered Sep 7, 2011 at 19:53

yoda

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3 Comments

jakobk Over a year ago

I solved it, apparently I can't use $(this) inside an ajax request while inside a loop : )

yoda Over a year ago

@jakobk haven't noticed that, you're "right". You can however use it if you use $.proxy with $.ajax.

jakobk Over a year ago

I used the ajax request inside an each loop, if I put a parameter with the each loop, and use that parameter later it works fine. Will the proxy function make sure that I am always getting the latest selector / key ?

Marc B · Accepted Answer · 2011-09-07 19:55:17Z

0

success: function(){$(this).text('data'); }

doesn't make much sense. $(this) in this context is going to be the success function, and you're trying to set its text content to the word 'data'?

Perhaps you mean this:

success: function(data) { $('#something_in_your_page').text(data); }

instead.

answered Sep 7, 2011 at 19:55

Marc B

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1 Comment

jakobk Over a year ago

True, typo.. but still if I use an alert,nothing happens

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