How to make Ruby regex expression with some conditional inputs

Question

This is my inputs looks like

format 1: 2022-09-23 18:40:45.846 I/getUsers: fetching data

format 2: 11:54:54.619 INFO loadingUsers:23 - visualising: "Entered to dashboard

This is the expression which is working for format one, i want to have the same (making changes to this) to handle both formats

^([0-9-]+ [:0-9.]+)\s(?<level>\w+)[\/+](?<log>.*)

it results as for format 1:

level I

message getUsers: fetching data

for 2nd it should be as

level INFO

message loadingUsers:23 - visualising: "Entered to dashboard

Help would be appreciated, Thanks

Wiktor Stribiżew · Accepted Answer · 2022-09-28 10:24:34Z

2

You can use

^([0-9-]+ [:0-9.]+|[0-9:.]+)\s(?<level>\w+)[\/+\s]+(?<log>.*)

See the Rubular demo.

Details:

^ - start of a line
([0-9-]+ [:0-9.]+|[0-9:.]+) - Group 1: one or more digits/hyphens, space, one or more digits/colons/dots, or one or more digits/colons/dots
\s - a whitespace
(?<level>\w+) - Group "level": one or more letters, digits or underscores
[\/+\s]+ - one or more slashes, + or whitespaces
(?<log>.*) - Group "log": zero or more chars other than line break chars as many as possible.

If you want to precise your Group 1 pattern (although I consider using a loose pattern fine in these scenarios), you can replace ([0-9-]+ [:0-9.]+|[0-9:.]+) with (\d{4}-\d{1,2}-\d{1,2} \d{1,2}:\d{1,2}:\d{1,2}\.\d+|\d{1,2}:\d{1,2}:\d{1,2}\.\d+), see this regex demo.

answered Sep 28, 2022 at 10:24

Wiktor Stribiżew

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