Regex to detect body of the arduino function

Question

Given a dummy function as such:

#include "DigiKeyboard.h"
        
void setup() {
            
#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

}
        
   void loop() {

  DigiKeyboard.delay(2000);

     }

I tried to get the content of the Setup function between the brackets and I tried

/[setup]+[(][a-zA-Z0-9=',]+[)][{]\n(.+?)\n+\s+[}]/gs

To get the result I want

#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

The problem is that the code was not written correctly because it works in the Regex site

But it doesn't work with javascript code and I think the reason is

regex single line flag /s

I searched a lot and read on Stackoverflow and the answers are not appropriate for the situation

My Regex

So even though the code works there, it won't work with JavaScript

var string = `


#include "DigiKeyboard.h"

void setup(){

#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

}

   void loop() {

  DigiKeyboard.delay(2000);

     }
        

`;



const regex = new RegExp("[setup]+[(][)][{]\n(.+?)\n+\s+[}]');

console.log(string.match(regex) == null);

@ITgoldman I don't know, but I think I've read before. This can be overcome by making it \} But in my case } will not be used inside the function — borma425
– borma425, Commented Sep 28, 2022 at 22:29

Peter Thoeny · Accepted Answer · 2022-09-28 23:24:15Z

1

This regex extracts the content within { ... } of setup:

var string = `

#include "DigiKeyboard.h"

void setup(){

#start_shift_3

DigiKeyboard.sendKeyStroke(0);

#end_shift_3

}

   void loop() {

  DigiKeyboard.delay(2000);

     }
`;

const m = string.match(/\bsetup\s*\(\)\s*\{\s*([^\}]*)/);
console.log(m ? m[1] : '(no match)');

Explanation of regex:

\b -- word boundary
setup -- expect literal setup string
\s*\(\)\s* -- scan over optional whitespace, (), whitespace
\{\s* -- scan over opening { and optional whitespace
([^\}]*) -- capture group scanning over everything not a closing }

Note that this will fail if your setup function contains curly braces. In that case you would need a proper language parser, or a multi-step regex that annotates the nesting level of the curly braces, so that you can identify the proper closing brace of the function.

edited Sep 28, 2022 at 23:24

answered Sep 28, 2022 at 22:55

Peter Thoeny

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1 Comment

borma425 Over a year ago

I won't need to add curly braces inside the function so this is a perfect answer Thank you for the very useful answer

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