I get "Undefine variable" from the following code.
This is all the code from index.php
<?php
include "globals.classes.php";
$anObj = new Globals();
logout();
function logout() {
echo $anObj->getName(); //Warning: Undefined variable $anObj
exit();
}
?>
I know passing $anObj in the parameter will work,
but is it possible to make it work without passing it through parameter?
I want to call a function this way..
logout();
not this...
logout($anObj);
That's because $anObj is out of scope. You need to either make logout() a member of Globals() and invoque it as:
<?php
include "globals.classes.php";
$anObj = new Globals();
$anObj->logout();
// In your class Global() you'll do something like this
class Globals {
function getName() {}
function logout() {
echo $this->getName();
exit();
}
}
?>
Another solution could be this:
<?php
include "globals.classes.php";
$anObj = new Globals();
echo $anObj->getName();
logout()
function logout() {
exit();
}
In that case you won't need logout(). But I guess you might want to do a few more things than just an exit()
logout($anObj);(besides using classes) is a much more common and recommended way of solving this problem. So I would recommend getting used to it rather than how can I get round it.