java (android) create JSONObject from scratch

Question

I'm trying to do something like:

public static final JSONObject MYOBJ = new JSONObject().put("value", "expression");

but eclipse get's mad and says there's an error on the line even though the tool tip shows No solutions available

I've tried changing JSONObject to type String and still the same prob. I'm shying away from hash maps and would really like to use JSON.

** EDIT - code location **

package ...

import ...

public class MyActivity extends Activity {
    public static final JSONObject MYOBJ = new JSONObject().put("value", "expression");

    ... // onCreate etc
}

Where do you exactly put this statement?

denolk
– denolk

2011-10-31 23:16:34 +00:00
Commented Oct 31, 2011 at 23:16 — denolk
– denolk, Commented Oct 31, 2011 at 23:16

Jacksonkr · Accepted Answer · 2013-09-10 02:57:05Z

6

Well it seems the JSONObject has a checked exception that must be handled. Try this

public static final JSONObject MYOBJ = new JSONObject(){
    {
        try {
            put("value", "expression");
        } catch(Exception e){
            e.printStackTrace();
        }
    }
};

edited Sep 10, 2013 at 2:57

Jacksonkr

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answered Oct 31, 2011 at 23:35

blessanm86

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2 Comments

Dave Newton Over a year ago

That's a pain, seems like a runtime exception would have been a better choice.

Dave Newton Over a year ago

Fortunately it's not final so a delegate class that throws an RTE is diable :)

david van brink · Accepted Answer · 2011-10-31 23:44:01Z

2

The result of put() is an Object. Do it in two lines and all is well.

public static final JSONObject MYOBJ = new JSONObject();
static {
  MYOBJ.put("value", "expression");
}

Note that the static final doesn't prevent the object from being changed, just that the original reference MYOBJ will always be the same object.

Edit: Ah, I was probably using a different flavor of the JSON library. Nonetheless, the above approach will probably work nicely. If the types all match, add some more parens to the original line.

edited Oct 31, 2011 at 23:44

answered Oct 31, 2011 at 23:27

david van brink

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6 Comments

Dave Newton Over a year ago

For which JSONObject? According to this it's a JSONObject developer.android.com/reference/org/json/…

Dave Newton Over a year ago

Pretty sure it's the exception ;)

Dave Newton Over a year ago

@Jackson The static doesn't have anything to do with that; final means the reference won't be changed once assigned, static means it's a class variable (as opposed to instance variable).

Jacksonkr Over a year ago

@Dave I suppose I addressed the usage wrong, but either way I gave a +1 in regards to line 2-4.

Dave Newton Over a year ago

@Jackson Oh, that; I see. Yep, static initialization block.

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