c# Multiple calls to a javascript function not working

Question

On a click event I call the same JavaScript function 3 times but the javascript function itself only execute once.

BLL.Common.executeJSFunction("DoSomething();");
BLL.Common.executeJSFunction("DoSomething();");
BLL.Common.executeJSFunction("DoSomething();");

The method:

public static void executeJSFunction(string jsFunction)
    {
        var page = HttpContext.Current.Handler as Page;
        ScriptManager.RegisterStartupScript(page, page.GetType(), "Exec", jsFunction, true);
    }

Java script function:

function DoSomething()
{
   alert('Hello Word');
}

ps: There is a ScriptManager and a update panel on the page just in case....

Joe · Accepted Answer · 2011-11-09 19:51:39Z

6

You overwrite the key with each function call, try:

BLL.Common.executeJSFunction("DoSomething();", "Exec1");
BLL.Common.executeJSFunction("DoSomething();", "Exec2");
BLL.Common.executeJSFunction("DoSomething();", "Exec3");

public static void executeJSFunction(string jsFunction, string key)
{
    var page = HttpContext.Current.Handler as Page;
    ScriptManager.RegisterStartupScript(page, page.GetType(), key, jsFunction, true);
}

answered Nov 9, 2011 at 19:51

Joe

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Comments

James Johnson · Accepted Answer · 2011-11-09 19:52:17Z

4

I believe this is happening because you're assigning the same key ("Exec") to the scripts. Assign a different key for each, or just do this:

BLL.Common.executeJSFunction("DoSomething();DoSomething();DoSomething();");

answered Nov 9, 2011 at 19:52

James Johnson

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Comments

Jakub Konecki · Accepted Answer · 2011-11-09 20:09:18Z

4

Right now you are registering the same code 3 times under the key Exec. You need to use different keys for your script registration:

public static void executeJSFunction(string key, string jsFunction)
    {
        var page = HttpContext.Current.Handler as Page;
        ScriptManager.RegisterStartupScript(page, page.GetType(), key, jsFunction, true);
    }

BLL.Common.executeJSFunction("Exec1", "DoSomething();");
BLL.Common.executeJSFunction("Exec2", "DoSomething();");
BLL.Common.executeJSFunction("Exec3", "DoSomething();");

See more here: http://msdn.microsoft.com/en-us/library/bb310408.aspx

edited Nov 9, 2011 at 20:09

answered Nov 9, 2011 at 19:52

Jakub Konecki

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IUnknown · Accepted Answer · 2011-11-09 19:52:00Z

2

Use different RegisterStartupScript method's key parameter value on each executeJSFunction method call. You may use this: ScriptManager.RegisterStartupScript(page, page.GetType(), Guid.NewGuid().ToString(), jsFunction, true);

answered Nov 9, 2011 at 19:52

IUnknown

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1 Comment

ShadowG Over a year ago

thx yuri, since I tried @JamesJohnson solution first I will mark his as resolved! but thx a lot!

ipr101 · Accepted Answer · 2011-11-09 20:03:39Z

2

I believe your problem is being caused because you're passing the same 'key' parameter ("Exec") each time you call the RegisterStartupScript function.

See here for further info - http://forums.asp.net/t/1365260.aspx/1

edited Nov 9, 2011 at 20:03

answered Nov 9, 2011 at 19:52

ipr101

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Deepak Kothari · Accepted Answer · 2014-03-21 15:50:00Z

0

If we need to call a javascript function more than once from c#,we must have to change the key parameter(3rd parameter),because browser will consider it as a same request and it will not process that request.Consider the below LOC

   var key="firstRequest";
    var page = HttpContext.Current.Handler as Page;
        ScriptManager.RegisterStartupScript(page, page.GetType(), key, "FunctionName()",true);

Now we have to change the key to call the same function again,

   key="secondRequest";
   var page = HttpContext.Current.Handler as Page;
        ScriptManager.RegisterStartupScript(page, page.GetType(), key, "FunctionName()",true);

answered Mar 21, 2014 at 15:50

Deepak Kothari

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