Regex to get a string following a string

Question

If i have a line that ends like

version is: 1.10.0.1001

i'm looking for a regex to get the version number but can't figure out how to get the string following "version is:"

ignore all the inputs upto : and consider the rest.

Prince John Wesley
– Prince John Wesley

2011-11-18 04:24:12 +00:00
Commented Nov 18, 2011 at 4:24 — Prince John Wesley
– Prince John Wesley, Commented Nov 18, 2011 at 4:24

Arindam · Accepted Answer · 2011-11-18 04:45:11Z

2

Use parantheses to capture values. If you only want the entire version value in one string, this would be enough

if(/version is:(.*)/.test(yourString)) {
    versionNum = RegExp.$1;
}

Here versionNum will store 1.10.0.1001.

But if you wanted the individual numbers between the dots, you would have to go with something like this:

if(/version is:(\d+\.)(\d+\.)(\d+.)(\d+)/.test(yourString)) {
    majorBuild = RegExp.$1;
    minorBuild = RegExp.$2;
    patch = RegExp.$3;
    revision = RegExp.$4;
}

Basically the variables will hold values like this

majorBuild = 1
minorBuild = 10
patch = 0
revision = 1001

Cheers!

answered Nov 18, 2011 at 4:45

Arindam

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Comments

snapfractalpop · Accepted Answer · 2011-11-18 04:23:44Z

0

use a capture (parentheses). Try

s/version is:(.*)/\1/g

also, what regex engine are you using? You may need to escape the colon, and determine if magic is on/off

or better yet, just remove version is: and everything before it

s/.*version is://g

answered Nov 18, 2011 at 4:23

$snapfractalpop's user avatar$

snapfractalpop

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1 Comment

snapfractalpop Over a year ago

what guarantees do you have about your input?

Prince John Wesley · Accepted Answer · 2011-11-18 04:36:04Z

0

Regex using java:

System.out.println("abcd version is:1.23.33.444".replaceAll("^(?:.*:)(.*)$","$1"));
System.out.println("abcd version is:1.23.33.444".replaceAll("^(?:.*:)",""));

answered Nov 18, 2011 at 4:36

Prince John Wesley

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Comments

Ryan Burnham · Accepted Answer · 2011-11-18 04:38:04Z

0

Nevermind i figured it out

(?<=version is: ).*

This won't include "version is: " in the match and will take any number of characters after it

answered Nov 18, 2011 at 4:38

Ryan Burnham

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