Adding multiple integers using arguments in function

Question

I am learning function in C. I want to sum multiple integers using arguments in function. I managed to write a code for adding two integers, but how if I want to add multiple integers and print the total of them? please guide me. Code which i wrote is;

#include<stdio.h>
#include<conio.h>
int sum(int a, int b, int c);
int main (void){
    int x,y,z;
    clrscr();
    printf("Enter first integer to add.\n");
    scanf("%d",&x);
    printf("Enter second integer to add.\n");
    scanf("%d",&y);
    sum(x, y, z);
    printf("Total = %d.\n",sum(x, y, z));
    getch();
    return 0;
}

int sum (int a, int b, int c){
    c=a+b;
    return c;
}

replace the body of sum with return a+b+c;. i'll let them explain why. — Dan D.
– Dan D., Commented Jan 28, 2012 at 9:14
What is you goal? Having a function with is able to add an arbitrary number of values? — Mithrandir
– Mithrandir, Commented Jan 28, 2012 at 9:15
I am sorry. I want take multiple inputs from user and when he press 'q' it should give me total of all integers he gave, i mean total of all integers taken from user. — AbdulAziz
– AbdulAziz, Commented Jan 28, 2012 at 9:18

shadyabhi · Accepted Answer · 2012-01-28 09:16:10Z

2

You can do something like this.

sum = 0;

while (ch == "y")
{
scanf("%d", &a);
sum+=a;
printf("Do you want to continue: ");
scanf("%c\n", &ch);
}

printf("%d", sum);

The idea is to have a variable sum whose initial value is 0.
Have a while loop that takes a integer a as input & add it to sum.
You can mantain a variable ch, which can be used to exit out of the loop. Only if the user enters "y", the user will be asked for integer again.

answered Jan 28, 2012 at 9:16

shadyabhi

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2 Comments

Mithrandir Over a year ago

should be scanf("%d", &a); and scanf("%d", &ch)

shadyabhi Over a year ago

@Mithrandir, oops, wrote in a hurry.

Riskhan · Accepted Answer · 2012-01-28 09:29:59Z

2

try this !

int main()
{
int var[100];
int count = 5;

printf("enter number %d number ", count);
for( int i = 0; i < count; i++ )
{
    scanf( "%d", &var[i] );
}

printf("sum=%d", sum(var, count) );

return 0;
 }


int sum( int var[], int count )
{
int sum = 0;
for( int i = 0; i < count; i++ )
{
    sum += var[i];
}

return sum;
 }

answered Jan 28, 2012 at 9:29

Riskhan

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1 Comment

AbdulAziz Over a year ago

Thanks it work. But i dont want to bound the user that he must enter 5 integers. i want it unlimited

Joey · Accepted Answer · 2012-01-28 09:14:56Z

0

Currently you're overwriting the third argument to the function with the sum of the first two and return it. This should probably change a bit.

Just think about how you'd write a sum of three numbers in mathematics and you should see the solution.

answered Jan 28, 2012 at 9:14

Joey

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