Why is parse_url() returning empty string in this case?
$url = "www.example.com";
$host = parse_url($url, PHP_URL_HOST);
print_r($host);
-
3Try adding http at the front of the URL?Alex– Alex2012-02-29 14:53:34 +00:00Commented Feb 29, 2012 at 14:53
Add a comment
|
3 Answers
The string is interpreted as relative URL:
// print_r(parse_url('www.vtechpcsupport.com'))
Array
(
[path] => www.vtechpcsupport.com
)
4 Comments
Juicy Scripter
Yep, but the weird thing is that
parse_url documentation states: "This function doesn't work with relative URLs." Looks like this isn't "seriously malformed URL" ;)
Andy
It also says "Partial URLs are also accepted, parse_url() tries its best to parse them correctly."
Felix Kling
@Juicy: Mmh. Maybe it is smarter than it claims. If I try
www.vtechpcsupport.com?foo=bar it correctly identifiers foo=bar as query string.Juicy Scripter
@FelixKling, the documentation is a bit controversing, it claims "parsing URLs and not URIs" (with some "modifications") and have link to RFC 3986 which is "URI Generic Syntax"
This is due to fact that www.vtechpcsupport.com isn't really a URL since it missing the scheme part (HTTP or so), try it like this:
$url = 'http://www.vtechpcsupport.com';
$var = parse_url($url,PHP_URL_HOST);
print($var);
3 Comments
Gumbo
It’s a URL but not one with a host.
Juicy Scripter
@Gumbo, it't really not ;) General URL Syntax
Marc B
@Gumbo: just because browsers default to http for bare hostnames doesn't make it a url - a scheme is required for a proper url. e.g. what if that was actually 'ftp.vtechpcsupport.com' and didn't have a web server running on it?
This is because www.vtechpcsupport.com is not a complete URL.
You are specifying PHP_URL_HOST so the function tries to extract just the host part of the URL, which doesn't exist as without a protocol being given the URL is treated as being relative -- so what you want to be the host name is interpreted as a (relative) path.
Try using:
$url='http://www.vtechpcsupport.com';
and you should get the behaviour you expect.
