Random background color from array - PHP

Question

I am a beginner when it comes to programming so I wanted to see if this would be the right way to code this. I was trying to generate a random background color from an array.

If there is something I'm missing or there is something I could do better please let me know.

<?php
    $background_colors = array('#282E33', '#25373A', '#164852', '#495E67', '#FF3838');

    $count = count($background_colors) - 1;

    $i = rand(0, $count);

    $rand_background = $background_colors[$i];
?>
<html>
    <head>

    </head>
    <body style="background: <?php echo $rand_background; ?>;">

    </body>
</html>

alex · Accepted Answer · 2012-03-08 02:22:02Z

6

That's pretty good.

However, I'd do it like so with array_rand()...

$background_colors = array('#282E33', '#25373A', '#164852', '#495E67', '#FF3838');

$rand_background = $background_colors[array_rand($background_colors)];

It is less code and more readable IMO.

answered Mar 8, 2012 at 2:22

alex

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1 Comment

Nick Meagher Over a year ago

Ahh okay, I was looking at that function but didn't know how to use it. Thank you.

Eman Jayme · Accepted Answer · 2015-12-11 09:28:28Z

3

function GenerateRandomColor()
{
    $color = '#';
    $colorHexLighter = array("9","A","B","C","D","E","F" );
    for($x=0; $x < 6; $x++):
        $color .= $colorHexLighter[array_rand($colorHexLighter, 1)]  ;
    endfor;
    return substr($color, 0, 7);
}

answered Dec 11, 2015 at 9:28

Eman Jayme

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Comments

HDJEMAI · Accepted Answer · 2016-07-16 23:31:22Z

2

<?php
    function bgcolor(){return dechex(rand(0,10000000));}
?>
<html>
    <head>
    </head>
    <body style="background:#<?php echo bgcolor(); ?>">    

    </body>
</html>

edited Jul 16, 2016 at 23:31

HDJEMAI

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answered Jul 16, 2016 at 21:54

Baale Ope

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1 Comment

alex Over a year ago

Looks like the OP wants a random item from a list - not an arbitrary random color.

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