PHP Array and current()

Question

I have an array in the format

Array
(
    [/Callum/] => Array
        (
            [0] => ##chan1
        )
    [/Adam/] => Array
        (
            [0] => ##chan2
        )   
    [/Chris)/] => Array
        (
            [0] => ##chan1
        )
    [/Mike*/] => Array
        (
            [0] => ##chan3
        )
)

And from this I use the below code to try and get the id of the array that each channel features in.

foreach($array as $row)
{

    if (in_array($buf['channel'],$row))
    {
        $return = $return." ".current(array_keys($array,$row));
    }
}

My problem is that current() doesnt seem to work the way I am expecting it to. Currently if the $buf /Callum/ twice rather than /Callum/ and /Chris/

array_keys is going to return a NEW array each time, which will always have its internal pointer set to the FIRST element. — Marc B
– Marc B, Commented Mar 15, 2012 at 17:14

Endijs · Accepted Answer · 2012-03-15 17:08:53Z

2

Why not:

foreach($array as $key => $row)
{

    if (in_array($buf['channel'],$row))
    {
        $return = $return . " " . $key;
    }
}

answered Mar 15, 2012 at 17:08

Endijs

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Comments

daker · Accepted Answer · 2012-03-15 17:16:48Z

0

Try this instead

foreach($array is $id => $row){
    $return .=" ".$id;
}

edit:

foreach($array is $id => $row){
    if($row[0] == $buf['channel']){
        echo $key; //This is your key
    }

}

edited Mar 15, 2012 at 17:16

answered Mar 15, 2012 at 17:09

daker

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2 Comments

mr.user1065741 Over a year ago

Is this to replace the entire foreach or just the internal if?

daker Over a year ago

The whole thing. But remove the $return and add your if-statement again, I think I missunderstood you..i'll edit my ans..

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