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You can use ${i%%.*}

e.g.

i=absdfsfd.b.c.dddd
echo "${i%%.*}"

will give output

absdfsfd

In your case:

 for i in *;do echo "${i%%.*}";done

Well do not use for i in ls. See Why *not* parse `ls` (and what to do instead)?

You can use ${i%%.*}. It will remove everything after first occurrence of dot including dot.

e.g.

i=absdfsfd.b.c.dddd
echo "${i%%.*}"

will give output

absdfsfd

In your case:

 for i in *;do echo "${i%%.*}";done

Well do not use for i in ls. See Why *not* parse `ls` (and what to do instead)?

You can use ${i%%.*}

e.g.

i=absdfsfd.b.c.dddd
echo "${i%%.*}"

will give output

absdfsfd

In your case:

 for i in *;do echo "${i%%.*}";done

Well do not use for i in ls.

You can use ${i%%.*}

e.g.

i=absdfsfd.b.c.dddd
echo "${i%%.*}"

will give output

absdfsfd

In your case:

 for i in *;do echo "${i%%.*}";done

Well do not use for i in ls. See Why *not* parse `ls` (and what to do instead)?

You can use ${i%%.*}

e.g.

i=absdfsfd.b.c.dddd
echo "${i%%.*}"

will give output

absdfsfd

In your case:

 for i in *;do echo "${i%%.*}";done

Well do not use for i in ls.

And if you really want to use pipes, then you can do

echo $(echo $i|cut -d. -f1)

In your case:

for i in *;do echo "$(echo $i|cut -d. -f1)";done

You can use ${i%%.*}

e.g.

i=absdfsfd.b.c.dddd
echo "${i%%.*}"

will give output

absdfsfd

In your case:

 for i in *;do echo "${i%%.*}";done

Well do not use for i in ls.