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ilkkachu
ilkkachu
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Imagine you have a silly script test.sh to which arguments are passed that would look like this:

bash test.sh arg1 arg2 arg3

with test.sh being a silly script that displays its command line:

#!/bin/bash
echo "$0 $*$*"

I would like to do the same using bash heredoc << to feed the script to bash. So I tried this :

bash <<'EOF' -- arg1 arg2 arg3
echo "$0 $*"
EOF

But it fails with error

bash: arg1: No such file or directory

Any idea ?

Imagine you have a silly script test.sh to which arguments are passed that would look like this:

bash test.sh arg1 arg2 arg3

with test.sh being a silly script that displays its command line:

#!/bin/bash
echo "$0 $*

I would like to do the same using bash heredoc << to feed the script to bash. So I tried this :

bash <<'EOF' -- arg1 arg2 arg3
echo "$0 $*"
EOF

But it fails with error

bash: arg1: No such file or directory

Any idea ?

Imagine you have a silly script test.sh to which arguments are passed that would look like this:

bash test.sh arg1 arg2 arg3

with test.sh being a silly script that displays its command line:

#!/bin/bash
echo "$0 $*"

I would like to do the same using bash heredoc << to feed the script to bash. So I tried this :

bash <<'EOF' -- arg1 arg2 arg3
echo "$0 $*"
EOF

But it fails with error

bash: arg1: No such file or directory

Any idea ?

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AdminBee
AdminBee
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creatldd1 creatldd1
creatldd1 creatldd1
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Bash : how to pass arguments to a heredoc script

Imagine you have a silly script test.sh to which arguments are passed that would look like this:

bash test.sh arg1 arg2 arg3

with test.sh being a silly script that displays its command line:

#!/bin/bash
echo "$0 $*

I would like to do the same using bash heredoc << to feed the script to bash. So I tried this :

bash <<'EOF' -- arg1 arg2 arg3
echo "$0 $*"
EOF

But it fails with error

bash: arg1: No such file or directory

Any idea ?