#!/bin/bash # # The Bash shell script executes a command with a time-out. # Upon time-out expiration SIGTERM (15) is sent to the process. If the signal # is blocked, then the subsequent SIGKILL (9) terminates it. # # Based on the Bash documentation example. # Hello Chet, # please find attached a "little easier" :-) to comprehend # time-out example. If you find it suitable, feel free to include # anywhere: the very same logic as in the original examples/scripts, a # little more transparent implementation to my taste. # # Dmitry V Golovashkin scriptName="${0##*/}" declare -i DEFAULT_TIMEOUT=9 declare -i DEFAULT_INTERVAL=1 declare -i DEFAULT_DELAY=1 # Timeout. declare -i timeout=DEFAULT_TIMEOUT # Interval between checks if the process is still alive. declare -i interval=DEFAULT_INTERVAL # Delay between posting the SIGTERM signal and destroying the process by SIGKILL. declare -i delay=DEFAULT_DELAY function printUsage() { cat < 0)); do sleep $interval kill -0 $$ || exit 0 ((t -= interval)) done # Be nice, post SIGTERM first. # The 'exit 0' below will be executed if any preceeding command fails. kill -s SIGTERM $$ && kill -0 $$ || exit 0 sleep $delay kill -s SIGKILL $$ ) 2> /dev/null & exec "$@"