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From: Paul H. <pmh...@gm...> - 2012-04-10 21:34:35
|
Ben Does "ax.set_xlim([0,50])" do what you want it to do? -paul On Tue, Apr 3, 2012 at 5:57 PM, Ben Harrison <ben...@li...> wrote: > I create my figure in my (non-interactive) script like so: > > import matplotlib.pyplot as plt > fig = plt.figure() > ax = fig.add_subplot(111) > ax.plot(...) > > Then I want to set the spacing of y grid to 50 units (axis units). Do I > need a method of the matplotlib.axis.Axis, or matplotlib.axes.Axes (or > are these the same??), or something else? > > Ben. > > > ------------------------------------------------------------------------------ > Better than sec? Nothing is better than sec when it comes to > monitoring Big Data applications. Try Boundary one-second > resolution app monitoring today. Free. > http://p.sf.net/sfu/Boundary-dev2dev > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users |
|
From: wiswit <cha...@gm...> - 2012-04-10 16:43:19
|
Dear all, I found that the numpoints in legend function for scatter plot is not working? import matplotlib as mat import matplotlib.pyplot as plt In [59]: mat.__version__ Out[59]: '1.1.0' #ordinary plot working fig=plt.figure() ax=fig.add_subplot(111) ax.plot(np.arange(10),'ro',label='tst') ax.legend(numpoints=1) plt.show() #but not scatter plot fig=plt.figure() ax=fig.add_subplot(111) ax.scatter(np.arange(10),np.arange(10),marker='o',label='tst') ax.legend(numpoints=1) plt.show() cheers, chao -- View this message in context: http://old.nabble.com/numpoints-in-legend%28%29-function-for-scatter-plot-is-not-working-in-matplotlib-1.1.0--tp33662785p33662785.html Sent from the matplotlib - users mailing list archive at Nabble.com. |
|
From: Chao Y. <cha...@gm...> - 2012-04-10 16:42:03
|
Dear all, I found that the numpoints in legend function for scatter plot is not working? import matplotlib as mat import matplotlib.pyplot as plt In [59]: mat.__version__ Out[59]: '1.1.0' #ordinary plot working fig=plt.figure() ax=fig.add_subplot(111) ax.plot(np.arange(10),'ro',label='tst') ax.legend(numpoints=1) plt.show() #but not scatter plot fig=plt.figure() ax=fig.add_subplot(111) ax.scatter(np.arange(10),np.arange(10),marker='o',label='tst') ax.legend(numpoints=1) plt.show() cheers, chao -- *********************************************************************************** Chao YUE Laboratoire des Sciences du Climat et de l'Environnement (LSCE-IPSL) UMR 1572 CEA-CNRS-UVSQ Batiment 712 - Pe 119 91191 GIF Sur YVETTE Cedex Tel: (33) 01 69 08 29 02; Fax:01.69.08.77.16 ************************************************************************************ |
|
From: wiswit <cha...@gm...> - 2012-04-10 16:22:54
|
Dear all, I use matplotlib 1.1.0. import matplotlib.pyplot as plt plt.plot(np.arange(10),'ro',mec='none') when I use plt.show(), there is only blank frame with axis not no points. but plt.plot(np.arange(10),'ro') will give good plot with read filled circles and black edges. plt.scatter(np.arange(10),np.arange(10),c='r',marker='o',edgecolor='none') is working fine. but I really think plt.plot is a very good and easy function if you don't make complex scatter points. and the circles look much nicer than that produced by plt.scatter (thought I don't know why as they use the same symble....) does anyone else have found the same ? thanks to all, Chao -- View this message in context: http://old.nabble.com/markeredgecolor-%28mec%29-in-the-plot-function-not-working--tp33662659p33662659.html Sent from the matplotlib - users mailing list archive at Nabble.com. |