matplotlib-users Mailing List for matplotlib

2010/7/30 Jeremy Conlin <jlc...@gm...>:
> I recently installed MPL on two Macs, one running 10.6 and another
> running 10.5.  When I try to plot, I get the following error:
>
> TclError: couldn't open
> "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/matplotlib/mpl-data/images/home.ppm":
> permission denied
>
> After checking, it's true that only the owner has read permissions.
> This is easy enough on my end, but I wonder if there is a problem with
> the distributed installer that should have the correct permissions for
> these images.
>
> Has anyone else seen this problem or is it just me?

Yes, we had this problem recently (Jul 12) on the list under subject
"permission denied error" started by Isaac Salazar <if...@la...>.

I didn't think it was a problem of the installer ... But seems it is.

Friedrich

2010/7/29 Waléria Antunes David <wal...@gm...>:
> Hi Benjamim,
>
> I made the changes as bellow and it displays the x-axis values formatted as
> expected, see my current image and my code. But, now i need to change the
> scale and the numbers of decimal places in order to appear on the graph like
> this: 3.0     3.1      3.2      ......           3.4

I think you need:

import matplotlib.ticker
[...]
axes.xaxis.set_major_locator(matplotlib.ticker.MaxNLocator(nbins=4)

maybe with an additional argument steps=[1, 2, 5, 10] as done by AutoLocator.

Your pastebin code has expired, so I don't know how your variables are
named now.

Friedrich

2010/7/29 Simon Friedberger <sim...@a-...>:
> For some magical reason when I set the ticks_position to none, setting
> the label_position to 'top' is ignored.
> Did you try this? Is it another command arrangement thing?
>
> On 09:26 Thu 29.07.10, Friedrich Romstedt wrote:
>> axis.set_label_position('top')
>> axis.set_ticks_position('none')

No, I didn't try, it was just a collection of commands, but I was
wrong: .set_label_position() refers to the axis label, this is the
single string labeling all the ticks with their "labels", e.g. "This
is $x$ axis.".

What you will want to use is .set_tick_params(top=True,
labeltop=False, labelbottom=False)  .

(But I didn't try this either. :-)  set_ticks_position() is just a
shorthand for .set_tick_params().

Friedrich

Bump.

Is this possible using mplot3d?? I would, also like to turn off the ticks
and the tick labels.



skavhaug wrote:
> 
> On Fri, Jun 11, 2010 at 4:50 PM, Benjamin Root <ben...@ou...> wrote:
>> Ola,
>>
>> Just to make sure, have you tried "ax.set_xticks([])"?
> 
> Yes, I have tried that, but without success. Looks like the tick-logic
> is overridden for 3d plotting. Or at least, I cannot figure out how it
> works.
> 
> Ola
> 
>> Ben Root
>>
>>
>>
>> On Fri, Jun 11, 2010 at 3:05 AM, Ola Skavhaug <ska...@si...> wrote:
>>>
>>> Hi,
>>>
>>> I'm trying to remove the xtickmarks and ytickmarks from a 3d plot,
>>> without any success.
>>>
>>> The example I experiment with is the following:
>>>
>>> from mpl_toolkits.mplot3d import axes3d
>>> import matplotlib.pyplot as plt
>>>
>>> fig = plt.figure()
>>> ax = axes3d.Axes3D(fig)
>>> X, Y, Z = axes3d.get_test_data(0.05)
>>> cset = ax.contour(X, Y, Z, 16, extend3d=True)
>>> ax.clabel(cset, fontsize=9, inline=1)
>>>
>>> #One try that didn't work
>>> ax.set_xticklabels("")
>>>
>>> plt.show()
>>>
>>> It looks like the final plot ignores all my efforts in turning the
>>> ticks off. Any help on this matter would be greatly appreciated.
>>>
>>> Regards,
>>> --
>>> Ola Skavhaug
>>> Research Programmer
>>> Simula Research Laboratory
>>>
>>>
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>>
>>
> 
> 
> 
> -- 
> Ola Skavhaug
> Research Programmer
> Simula Research Laboratory
> 
> ------------------------------------------------------------------------------
> ThinkGeek and WIRED's GeekDad team up for the Ultimate 
> GeekDad Father's Day Giveaway. ONE MASSIVE PRIZE to the 
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> 

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Ryan May <rma...@pu...> writes:
> On Jul 30, 2010, at 14:34, Nikolaus Rath <Nik...@pu...> wrote:
>
>> Hi,
>> 
>> Consider this:
>> 
>> X = np.linspace(0.70, 1.1, 100)
>> Y = np.linspace(-1.19, 1.19, 70)
>> (Xs, Ys) = np.meshgrid(X, Y)
>> Z = np.sqrt((Xs-0.9)**2 + Ys**2) - 0.10
>> fig = plt.figure()
>> ax = fig.add_subplot(111)
>> ax.contour(X, Y, Z)
>> fig.show()
>> 
>> This works, but gives the y axis a different scale than the x axis so
>> the ellipses look like circles.
>> 
>> How can I get the same scale for the x- and y-axis?
>> 
>> I tried to set ax.set_autoscale_on(False), but that resulted in a
>> totally different part of the coordinate system being 
>
> Try:
>
> ax.set_aspect('equal')

Works perfectly, thanks!


   -Nikolaus

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