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From: Christopher B. <Chr...@no...> - 2008-06-04 23:40:30
|
Bryan Fodness wrote:
> I tried posting this to numpy, but my posts never show up.
odd -- it works fine for me -- are you subscribed?
anyway:
>>> import numpy as np
>>> a = np.arange(100).reshape((10,10))
>>> b = np.ones((5,7)) * 30
>>> a
array([[ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
[20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
[30, 31, 32, 33, 34, 35, 36, 37, 38, 39],
[40, 41, 42, 43, 44, 45, 46, 47, 48, 49],
[50, 51, 52, 53, 54, 55, 56, 57, 58, 59],
[60, 61, 62, 63, 64, 65, 66, 67, 68, 69],
[70, 71, 72, 73, 74, 75, 76, 77, 78, 79],
[80, 81, 82, 83, 84, 85, 86, 87, 88, 89],
[90, 91, 92, 93, 94, 95, 96, 97, 98, 99]])
>>> b
array([[ 30., 30., 30., 30., 30., 30., 30.],
[ 30., 30., 30., 30., 30., 30., 30.],
[ 30., 30., 30., 30., 30., 30., 30.],
[ 30., 30., 30., 30., 30., 30., 30.],
[ 30., 30., 30., 30., 30., 30., 30.]])
>>> a[3:8, 2:9] += b
>>> a
array([[ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[ 10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
[ 20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
[ 30, 31, 62, 63, 64, 65, 66, 67, 68, 39],
[ 40, 41, 72, 73, 74, 75, 76, 77, 78, 49],
[ 50, 51, 82, 83, 84, 85, 86, 87, 88, 59],
[ 60, 61, 92, 93, 94, 95, 96, 97, 98, 69],
[ 70, 71, 102, 103, 104, 105, 106, 107, 108, 79],
[ 80, 81, 82, 83, 84, 85, 86, 87, 88, 89],
[ 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]])
>>>
--
Christopher Barker, Ph.D.
Oceanographer
Emergency Response Division
NOAA/NOS/OR&R (206) 526-6959 voice
7600 Sand Point Way NE (206) 526-6329 fax
Seattle, WA 98115 (206) 526-6317 main reception
Chr...@no...
|
|
From: Bryan F. <bry...@gm...> - 2008-06-04 20:20:11
|
I tried posting this to numpy, but my posts never show up. So, I was hoping someone here might be able to help me. I have two arrays that are different sizes and i would like to be able to add them for plotting. If I have an array a and b, [[1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9] [1 2 3 4 5 6 7 8 9]] [[0 0 0 0 0] [0 3 3 3 0] [0 3 3 3 0] [0 3 3 3 0] [0 0 0 0 0]] but I would like to change b to look like this, [[0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0] [0 0 3 3 3 3 3 0 0] [0 0 3 3 3 3 3 0 0] [0 0 3 3 3 3 3 0 0] [0 0 3 3 3 3 3 0 0] [0 0 3 3 3 3 3 0 0] [0 0 3 3 3 3 3 0 0] [0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0]] so I can get the sum of a and b. My data will not be regular like these. I have a 400x60 array with irregular data that I would like as a 400x400 array. Does anybody know of an easy way to accomplish this? Bryan -- "The game of science can accurately be described as a never-ending insult to human intelligence." - João Magueijo |
|
From: KURT P. <pet...@ms...> - 2008-06-04 19:41:47
|
My fault. that last error was because I re-installed matplotlib and forgot to "re-change" the backend to TkAgg. Sorry. Everything seems to be working again now (although a bit slower). Kurt |
|
From: KURT P. <pet...@ms...> - 2008-06-04 19:17:50
|
Looks like your latest compile includes the full-res data. Kurt |
|
From: KURT P. <pet...@ms...> - 2008-06-04 19:03:13
|
Well, installing the highres data into the 'data' directory didn't help. Kurt |
|
From: KURT P. <pet...@ms...> - 2008-06-04 18:50:52
|
Jeff, Got it and it seemed to install.
Well... as luck would have it, I still have a problem. I think I know what
is causing it, though. I was using the high-res data, and the "upgrade"
nukes that data. Here's the message I'm getting along with the code
snippet, just to make sure I'm on the right track for a solution:
Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Python25\Lib\lib-tk\Tkinter.py", line 1403, in __call__
return self.func(*args)
File "C:\Documents and
Settings\kpeters\smworkspace\parsesmExcelFile\src\readParse\ExcelClass.py",
line 405, in callback
populate_banddata(fileToOpen)
File "C:\Documents and
Settings\kpeters\smworkspace\parsesmExcelFile\src\readParse\ExcelClass.py",
line 383, in populate_banddata
populate_location_map(sheetnumber, sP, txInfo)
File "C:\Documents and
Settings\kpeters\smworkspace\parsesmExcelFile\src\readParse\ExcelClass.py",
line 100, in populate_location_map
projection='lcc', lat_1=33, lat_2=45, lon_0=-95, resolution='l')
TypeError: 'module' object is not callable
Code Snippet:
m1 = basemap(llcrnrlon=-119, llcrnrlat=22, urcrnrlon=-64, urcrnrlat=49,
\
projection='lcc', lat_1=33, lat_2=45, lon_0=-95,
resolution='l')
shp_info =
m1.readshapefile(r'C:\Python25\Lib\basemap-0.99\examples\citiesx020',
'states', drawbounds=True)
Any hints on what to do now that I am downloading the fullres?
Regards,
Kurt
|
|
From: Margherita V. w. <vi...@fn...> - 2008-06-04 18:36:47
|
HI , thank you very much for the quick reply, i have an older version (which is not up to me upgrade) so the subplots_adjust worked just fine. Thanks again. bye for now Margherita |
|
From: Matthias M. <Mat...@gm...> - 2008-06-04 16:25:31
|
Hi Margherita, On Wednesday 04 June 2008 18:01:47 Margherita Vittone wiersma wrote: > Hi all, > i have a plot on which the x axix has timestamps info; i would like to > control the size of the edge or border (not sure whta is the proper word) > so the there is enough space between the real plot and the outer border so > that the x labels are not cut out. I rotate the xlabel also but still i > don't have enough space; how do i control that feature? Even in one of the > demo examples i see the same problem, example in date_demo_convert.py > where you can't see the x full lable. First of all I cannot confirm your observation with the online version of the example at http://matplotlib.sourceforge.net/examples/pylab/date_demo_convert.py Maybe the function "fig.autofmt_xdate" is not included in your version of the example. With that function you have many possibilities to change the x-date-format, e.g. fig.autofmt_xdate(bottom=0.3, rotation=45) or you can extend the space between the axes and the border of the figure yourself using subplots_adjust(bottom=0.2) best regards Matthias |
|
From: John H. <jd...@gm...> - 2008-06-04 16:24:21
|
On Wed, Jun 4, 2008 at 11:01 AM, Margherita Vittone wiersma <vi...@fn...> wrote: > Hi all, > i have a plot on which the x axix has timestamps info; i would like to control the size > of the edge or border (not sure whta is the proper word) so the there is enough space between > the real plot and the outer border so that the x labels are not cut out. I rotate the xlabel also > but still i don't have enough space; how do i control that feature? Even in one of the demo examples > i see the same problem, example in date_demo_convert.py where you can't see the x full lable. What you are asking for is controlled by the "subplots_adjust" parameter fig.subplots_adjust(bottom=0.2) but for dates in particular we have a helper function which: * adjusts the bottom * rotates the ticks * right aligns them Try fig.autofmt_xdate() with recent matplotlib releases. JD |
|
From: Margherita V. w. <vi...@fn...> - 2008-06-04 16:01:50
|
Hi all, i have a plot on which the x axix has timestamps info; i would like to control the size of the edge or border (not sure whta is the proper word) so the there is enough space between the real plot and the outer border so that the x labels are not cut out. I rotate the xlabel also but still i don't have enough space; how do i control that feature? Even in one of the demo examples i see the same problem, example in date_demo_convert.py where you can't see the x full lable. Thank all you much Margherita |
|
From: Matthieu B. <mat...@gm...> - 2008-06-04 12:08:27
|
Hi, Thanks for the tips, I'll try that :) Matthieu 2008/6/4 Matthias Michler <Mat...@gm...>: > Hi Matthieu, > > I'm not sure if somebody else already answered to your question and I don't > know the best way to achieve what you need, but I suggest the following > work-around: > > scatter(x, x**2.4, marker='s', color='r', s=25, label="_") > # with no label > > plot([0], [0], ls='', marker='s', color='r', ms=5, mew=0, label="my label") > # plot somewhere outside the shown axis with the preferred label > > legend() > > Best regards > Matthias > > On Friday 30 May 2008 11:20:08 Matthieu Brucher wrote: > > Hi, > > > > I'd like to plot three scatter plots on the same figure, each with > > different symbols. Associated to these scatter plots, I'd like to put a > > legend. For the moment, the legend is based on one of the color of the > > associated scatter plot, but it is not relevant. Indeed, the colors are > not > > identical inside one scatter plot, so the displayed color is > > discriminating. So I'd like to display the symbol (circle, square, cross, > > ...) instead of the color rectangle. Is it possible ? > > > > Thanks, > > > > Matthieu > > > > ------------------------------------------------------------------------- > Check out the new SourceForge.net Marketplace. > It's the best place to buy or sell services for > just about anything Open Source. > http://sourceforge.net/services/buy/index.php > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > -- French PhD student Website : http://matthieu-brucher.developpez.com/ Blogs : http://matt.eifelle.com and http://blog.developpez.com/?blog=92 LinkedIn : http://www.linkedin.com/in/matthieubrucher |
|
From: Matthias M. <Mat...@gm...> - 2008-06-04 08:33:09
|
Hi Matthieu, I'm not sure if somebody else already answered to your question and I don't know the best way to achieve what you need, but I suggest the following work-around: scatter(x, x**2.4, marker='s', color='r', s=25, label="_") # with no label plot([0], [0], ls='', marker='s', color='r', ms=5, mew=0, label="my label") # plot somewhere outside the shown axis with the preferred label legend() Best regards Matthias On Friday 30 May 2008 11:20:08 Matthieu Brucher wrote: > Hi, > > I'd like to plot three scatter plots on the same figure, each with > different symbols. Associated to these scatter plots, I'd like to put a > legend. For the moment, the legend is based on one of the color of the > associated scatter plot, but it is not relevant. Indeed, the colors are not > identical inside one scatter plot, so the displayed color is > discriminating. So I'd like to display the symbol (circle, square, cross, > ...) instead of the color rectangle. Is it possible ? > > Thanks, > > Matthieu |