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From: questions a. <que...@gm...> - 2011-11-06 21:30:27
|
no that didn't work and I am back to thinking it is not the dates fault, this is because if I only choose a section of my array that I know doesn't have any NANs it works fine. Is there a way to tell is to skip/ignore these? On Sat, Nov 5, 2011 at 8:50 AM, Stan West <sta...@nr...> wrote: > ** > > *From:* questions anon [mailto:que...@gm...] > *Sent:* Wednesday, November 02, 2011 17:17 > > Thanks, I think you are right about the datetimes for the x axis causing > the problem. > Does anyone have any ideas how to resolve this? > > Does it help to call ax.xaxis_date() before your calls to plt.plot()? > |
|
From: klo uo <kl...@gm...> - 2011-11-06 20:58:31
|
Like in Basemap examples: http://matplotlib.github.com/basemap/users/examples.html (topographic image in the middle of page) ground 0 has some yellow/orange color making seas and oceans coasts in that same, color instead light blue (as we'd all expect I guess) So how to shift this particular colormap (cm.GMT_haxby) up a bit, so that I get expected colors? |
|
From: <kra...@gm...> - 2011-11-06 19:18:32
|
/usr/lib/pymodules/python2.7/mpl_toolkits/mplot3d/axes3d.pyc in
set_autoscale_on(self, b)
252 """
253 Axes.set_autoscale_on(self, b)
--> 254 self.set_autoscalez_on(self, b)
255
256 def set_autoscalez_on(self, b) :
TypeError: set_autoscalez_on() takes exactly 2 arguments (3 given)
I believe there is one self too much.
Regards
Stefan
|
|
From: Gousios G. <gg...@wi...> - 2011-11-06 18:25:06
|
Thanks!
Now,it's better it gives me my 10 points but it supposed to give me the
2 axes with values from 0-1000,but they are not.
data=[]
for i in range(0,1000,100):
mydata=(sc.array([i,rw1.MeanSquareDistance1d(i,np)])).tolist()
data.append(mydata)
print(data)
fig3=plt.figure()
x,y=sc.transpose(data)
plt.plot(x,y,'bo')
plt.show()
(It isn't affected if i do plt.axis([0, 1000, 0, 1000])
|
|
From: Ben B. <bbr...@gm...> - 2011-11-06 18:16:38
|
You can also do x,y = zip(*pts) If you don't feel like importing numpy. Ben On Sun, Nov 6, 2011 at 12:49 PM, Tony Yu <ts...@gm...> wrote: > > > On Sun, Nov 6, 2011 at 8:20 AM, Gousios George <gg...@wi...>wrote: > >> Hello, >> Is there a way?Like the title says? >> I have a 2d list : >> > [[ 0 1] >> > [ 1 1] >> > [ 1 0] >> > [ 2 0] >> > [ 1 0] >> > [ 2 0] >> > [ 1 0] >> > [ 0 0] >> > [ 1 0] >> > [ 1 -1]] >> >> and i want to do the "listplot' from mathematica. >> > > I don't know of a plot function to do this, but one extra line of code > should suffice: > > pts = [[0, 1], > [1, 1], > [1, 0], > [2, 0], > [1, 0], > [2, 0], > [1, 0], > [0, 0], > [1, 0], > [1,-1]] > x, y = np.transpose(pts) > plt.plot(x, y) > > > Best, > -Tony > > > > ------------------------------------------------------------------------------ > RSA(R) Conference 2012 > Save $700 by Nov 18 > Register now > http://p.sf.net/sfu/rsa-sfdev2dev1 > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > |
|
From: Tony Yu <ts...@gm...> - 2011-11-06 17:49:57
|
On Sun, Nov 6, 2011 at 8:20 AM, Gousios George <gg...@wi...>wrote:
> Hello,
> Is there a way?Like the title says?
> I have a 2d list :
> > [[ 0 1]
> > [ 1 1]
> > [ 1 0]
> > [ 2 0]
> > [ 1 0]
> > [ 2 0]
> > [ 1 0]
> > [ 0 0]
> > [ 1 0]
> > [ 1 -1]]
>
> and i want to do the "listplot' from mathematica.
>
I don't know of a plot function to do this, but one extra line of code
should suffice:
pts = [[0, 1],
[1, 1],
[1, 0],
[2, 0],
[1, 0],
[2, 0],
[1, 0],
[0, 0],
[1, 0],
[1,-1]]
x, y = np.transpose(pts)
plt.plot(x, y)
Best,
-Tony
|
|
From: Gousios G. <gg...@wi...> - 2011-11-06 13:20:32
|
Hello, Is there a way?Like the title says? I have a 2d list : > [[ 0 1] > [ 1 1] > [ 1 0] > [ 2 0] > [ 1 0] > [ 2 0] > [ 1 0] > [ 0 0] > [ 1 0] > [ 1 -1]] and i want to do the "listplot' from mathematica. Thanks! |
|
From: Gökhan S. <gok...@gm...> - 2011-11-06 04:39:10
|
Hi, I was wondering this about 2 years ago [ http://old.nabble.com/Gradient-color-on-a-line-object-td25630375.html] Just today, I have found a very simple way to do this in mpl. x = np.linspace(0, 2*np.pi, 3600) y = np.sin(x) plt.scatter(x,y,c=range(len(x)), marker='_', s=1) Setting the marker to underscore character and choosing a relatively low size value makes the line appear just like I wanted. (Provided, using lengthy data points) Is this a very known trick? If not so, what is your favorite color gradient approach for a simple plot? Cheers, -- Gökhan |
|
From: Gökhan S. <gok...@gm...> - 2011-11-06 04:33:36
|
Hi, These two links seem to be broken here: http://matplotlib.sourceforge.net/examples/api/demo_affine_image_00.html http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_00.html |