matplotlib-users Mailing List for matplotlib

Hi,

Did anyone have any insight on this?  Alternatively, anyone know why there
has been little uptake on this question ...(apologies that it was
accidentally sent twice)?

Leo

On Tue, Feb 3, 2009 at 11:42 PM, Leo Trottier <le...@co...> wrote:

> Matplotlib 0.98.5.2
> Location: C:\leo\.matplotlib
> Running Windows XP SP2
> Obtained from pythonxy v. 2.1.10
> No rc customizations ...
>
> I've been having a devil of a time getting my rcParams to update
> mid-script.  Perhaps this isn't possible, but if that's so, it's not
> entirely clear.  Even if it is so, this is seemingly a defect, because in an
> interactive session one expects quite different behavior (and no amount of
> iPython %reset-ing seems to be able to help).
>
> Note that manually setting the font (or what have you) in *title* works
> fine.
>
> Here is some example code:
>
> ############## BEGIN #########
> import matplotlib
> from matplotlib import rc, rcParams, rcdefaults
> from matplotlib.pyplot import plot, show, figure, title
>
> print matplotlib.__version__
> print matplotlib.get_configdir()
> print
> print "rcParams['font.sans-serif']:", rcParams['font.sans-serif']
> print 'family is:', rcParams['font.family']
> print
> figure(4)
> title('This should be in a sans-serif font')
> show()
>
> rcParams['font.sans-serif'] = rcParams['font.monospace']
> print "rcParams['font.sans-serif']:", rcParams['font.sans-serif']
> print 'family is:', rcParams['font.family']
> print
> figure(1)
> title('This should be in a monospace font')
> show()
>
> rcParams['font.sans-serif'] = rcParams['font.serif']
> print "rcParams['font.sans-serif']:", rcParams['font.sans-serif']
> print 'family is:', rcParams['font.family']
> print
> figure(2)
> title('This should be in a serif font')
> show()
>
> rcdefaults()
> print "rcParams['font.sans-serif']:", rcParams['font.sans-serif']
> print 'family is:', rcParams['font.family']
> print
> figure(3)
> title('This should be back to a sans-serif font')
> show()
> ######### END ####################
>

Sure.  Just send me a note when the src is ready.

- Charlie

On Sun, Feb 8, 2009 at 3:46 PM, John Hunter <jd...@gm...> wrote:
> We have accumulated a number of bug fixes in our stable release
> branch, so I would like to release the 3rd bugfix release.  Please
> test and report any problems
>
>  http://matplotlib.sourceforge.net/release-candidates/matplotlib-0.98.5.3.tar.gz
>
> Charlie, will you have any time early next week for the windows
> builds?  I can handle the OSX and src release.
>
> Thanks,
> JDH
>

Hi everyone,

I am plotting a figure where I need two independent x axes and two  
independent y axes. I've tried to use both twinx and twiny at the  
same time, and this works to some extent, but it looks like it is  
plotting the labels for the bottom x axis and the right-hand y axis  
twice, which makes me think that I must be doing something wrong (the  
numbers appear more 'bold'). The code is below. Is there a better way  
to do this?

In reality, I don't need a different scale for the opposite axes, but  
I want to specify different Locator functions, but I assume that  
creating a new axes instance as done below is the only way to do this?

Thanks for any advice,

Thomas

###
fig = figure()
ax  = fig.add_subplot(111)
ax2 = ax.twinx().twiny()
for tick in ax.yaxis.get_major_ticks():
	tick.label1On = True
	tick.label2On = False
	tick.tick1On = True
	tick.tick2On = False
for tick in ax.xaxis.get_major_ticks():
	tick.label1On = True
	tick.label2On = False
	tick.tick1On = True
	tick.tick2On = False
for tick in ax2.yaxis.get_major_ticks():
	tick.label1On = False
	tick.label2On = True
	tick.tick1On = False
	tick.tick2On = True
for tick in ax2.xaxis.get_major_ticks():
	tick.label1On = False
	tick.label2On = True
	tick.tick1On = False
	tick.tick2On = True
ax.scatter([0.4],[0.6])
ax2.scatter([10.],[10.])
draw()
###

We have accumulated a number of bug fixes in our stable release
branch, so I would like to release the 3rd bugfix release.  Please
test and report any problems

  http://matplotlib.sourceforge.net/release-candidates/matplotlib-0.98.5.3.tar.gz

Charlie, will you have any time early next week for the windows
builds?  I can handle the OSX and src release.

Thanks,
JDH

Never mind - I just saw the very timely e-mail from Jouni.

Thanks!

On Sun, 8 Feb 2009 14:16:59 -0600
Alan Jackson <al...@aj...> wrote:

> Trying to find a simple way to shrink the tick labels for this plot -
> since I can have many tiny histograms, the labels need to be smaller,
> but it isn't obvious to me how to simply shrink them.
> 
> code snippet...
> 
> num = len(datasets)
> fig = plt.figure()
> rows = np.int(np.sqrt(num))
> cols = np.int(float(num)/float(rows)+.9)
> for i in range(num):
>     ax = fig.add_subplot(rows, cols, i+1)
>     ax.hist(datasets[i][np.isfinite(datasets[i])], bins=60 )
>     ax.set_xlabel(labels[i], size = 9)
>     ax.set_ylabel('Counts', size = 9)
> plt.show()
> 
> 
> -- 
> -----------------------------------------------------------------------
> | Alan K. Jackson            | To see a World in a Grain of Sand      |
> | al...@aj...          | And a Heaven in a Wild Flower,         |
> | www.ajackson.org           | Hold Infinity in the palm of your hand |
> | Houston, Texas             | And Eternity in an hour. - Blake       |
> -----------------------------------------------------------------------
> 
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-- 
-----------------------------------------------------------------------
| Alan K. Jackson            | To see a World in a Grain of Sand      |
| al...@aj...          | And a Heaven in a Wild Flower,         |
| www.ajackson.org           | Hold Infinity in the palm of your hand |
| Houston, Texas             | And Eternity in an hour. - Blake       |
-----------------------------------------------------------------------

Trying to find a simple way to shrink the tick labels for this plot -
since I can have many tiny histograms, the labels need to be smaller,
but it isn't obvious to me how to simply shrink them.

code snippet...

num = len(datasets)
fig = plt.figure()
rows = np.int(np.sqrt(num))
cols = np.int(float(num)/float(rows)+.9)
for i in range(num):
    ax = fig.add_subplot(rows, cols, i+1)
    ax.hist(datasets[i][np.isfinite(datasets[i])], bins=60 )
    ax.set_xlabel(labels[i], size = 9)
    ax.set_ylabel('Counts', size = 9)
plt.show()


-- 
-----------------------------------------------------------------------
| Alan K. Jackson            | To see a World in a Grain of Sand      |
| al...@aj...          | And a Heaven in a Wild Flower,         |
| www.ajackson.org           | Hold Infinity in the palm of your hand |
| Houston, Texas             | And Eternity in an hour. - Blake       |
-----------------------------------------------------------------------

A B <pyt...@gm...> writes:

>    f = pyplot.figure()

When you do this, matplotlib retains a reference to the figure until you
close it so that you can go back to it with e.g. figure(4). So add
pyplot.close(f) to your script. Or, even better, use the object-oriented
API. To get started with that, see

http://matplotlib.sourceforge.net/leftwich_tut.txt

-- 
Jouni K. Seppänen
http://www.iki.fi/jks

Hi,

Following is my post to the Django mailing list from yesterday. The response
was that Django isn't known to leak memory so there should be something off
with matplotlib or rather that way I am using it.
Hopefully someone here could comment on what could be causing the leaks.
Thanks in advance.


----

I am using matplotlib/pyplot on my site to dynamically generate PNG
plots. And I am experiencing dramatic memory leaks. Within 10-15
hits,  my Apache process grows from 15-20M to 100M.

I am using Django 1.0.2-final, Apache 2.2.1, Python 2.4.3, matplotlib
0.98.5.2. The leak happens under both Apache (with mod_wsgi 2.3) and
the development server. My OS is RHEL5.

Below is a simple code snippet that causes the leak. Please let me
know if I am doing something wrong or if there is a better way to
write this. Thanks.



from matplotlib import pyplot

def test_graph (request):

   f = pyplot.figure()
   ax = f.add_subplot(111)
   ax.plot([1,2,3])

   ax.fill_between([1,2,3],[1,2,3],[1.1,2.1,3.1])

   ax.grid(True)
   ax.legend(['hello'],
             'upper right', shadow=True, fancybox=True)
   ax.set_xlabel('Time')
   ax.set_ylabel('Value ')

   f.text(.5, 0.93, 'my title', horizontalalignment='center')

   response = HttpResponse(content_type='image/png')

### both ways causes a leak

   f.savefig( response, format = 'png' )
OR
   canvas = FigureCanvas(f)
   canvas.print_png(response)
   canvas = None

   ax = None
   f = None

   return response

Hi all,

I have noticed a funny behaviour when using twinx to do two plots on the
same axes: the xticklabels are printed twice, once for each axes. This
shows up as slightly thicker labels than for a single axes. It is
particularly visible for ps or pdf output, but can be seen also in an
interactive session.

I can also see this in the figure shown for the two_scales.py example
(http://matplotlib.sourceforge.net/_images/two_scales.png), where the
xticklabels are thicker than the yticklabels (though it is not so
apparent due to different colours. I therefore assume it is not just my
installation. (Adding

for tl in ax2.get_xticklabels():
    tl.set_fontsize(16)

just before the last plt.show() in two_scales.py makes it even more
visible)

Does anyone know of a reasonable work-around? Surely it is not the
intended behaviour?

Thanks for any help,
Christoffer Åberg