matplotlib-users Mailing List for matplotlib

Hello,

I have just chaged over to the Qt4Agg backend so I can use Pierre Raybaut's
addition of editing cuves and parameters (thanks for this functionality).  I
have found a small issue.  Whenever I apply changes with more than one
trace/curve, the colour of the second curve changes.  The example below is
enough to show the issue:

from matplotlib import pyplot
import numpy as np

a = np.random.rand(100)
b =a*1.5
fig = pyplot.figure()
ax = fig.add_subplot(111)
ax.plot(a)
ax.plot(b)
pyplot.show()

The  example above changes second trace from a default of green to a light
green when I use the edit button.  Just pressing 'apply' without any changes
should be enough to trigger the change.  It appears that the addin is not
getting the correct color from the plot and so apply is appying the
incorrect color back into the plot.

Also if I try to set color for a trace like this:
fig = pyplot.figure()
ax = fig.add_subplot(111)
ax.plot(a,'r')
pyplot.show()
It works but then when I press the edit curves button, I get:

Traceback (most recent call last):
  File "C:\Python26\lib\site-packages\matplotlib\backends\backend_qt4.py",
line 469, in edit_parameters
    figureoptions.figure_edit(axes, self)
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\figureoptions.py",
line 154, in figure_edit
    icon=get_icon('qt4_editor_options.svg'), apply=apply_callback)
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\formlayout.py",
line 460, in fedit
    dialog = FormDialog(data, title, comment, icon, parent, apply)
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\formlayout.py",
line 384, in __init__
    parent=self)
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\formlayout.py",
line 362, in __init__
    widget = FormComboWidget(data, comment=comment, parent=self)
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\formlayout.py",
line 344, in __init__
    widget = FormWidget(data, comment=comment, parent=self)
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\formlayout.py",
line 233, in __init__
    self.setup()
  File
"C:\Python26\lib\site-packages\matplotlib\backends\qt4_editor\formlayout.py",
line 256, in setup
    selindex = value.pop(0)
AttributeError: 'tuple' object has no attribute 'pop'

I am on version 1.0.0 and XP


Thanks,
Bevan




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On Sat, Sep 18, 2010 at 1:03 PM, Benjamin Root <ben...@ou...> wrote:
>
> I'll admit that I am not very familiar with how these step plots are done.
> Maybe it should be the 'drawstyle' kwarg that should be over-riden, not
> 'linestyle'?
>
> Ben Root
>

This seems like more reasonable to me. When I update
/matplotlib/lib/axes.py:

kwargs['linestyle'] = 'steps-' + where -> kwargs['drawstyle'] = 'steps-' +
where

then I get the expected behavior.

-- 
Gökhan

Thanks, that works fantastically !

-- Forest.

On Fri, Sep 17, 2010 at 9:23 PM, Benjamin Root <ben...@ou...> wrote:
> On Fri, Sep 17, 2010 at 8:05 PM, Forest Yang <yzi...@gm...> wrote:
>>
>> Hi
>>
>>   I have a function z(x, y) on a regular grid. But some of the value
>> z are not defined on (x,y). I want to plot the contour or contourf of
>> z on (x,y) but exclude specific (x,y) points.
>> How can I do it ? Right now I just draw small colored square
>> (rectangular) around defined (x,y) the color is not smooth since no
>> interpolation like contour or contourf.
>>
>> Thanks.
>>
>> Forest.
>>
>
> Forest,
>
> There are a few ways to do this.  If you have a recent enough version of
> matplotlib, you can use masked arrays, and the contourf will just ignore
> those data points.  One could also use NaNs and make sure that the clim (the
> limits on z that you wish to display a color for) is defined.
>
> To make a masked array is easy.  Imagine you wish to exclude any value less
> than zero (assume z is defined):
>
> import numpy.ma as ma
> z_masked = ma.masked_array(z, mask=(z < 0.))
>
> And then just use the  masked array in your contourf as you would the
> regular numpy array.
>
> I hope that helps!
> Ben Root
>
>