matplotlib-users Mailing List for matplotlib

On 02/09/10 00:13, Benjamin Root wrote:
>
> I am not sure I understand what you mean.  Could you please attach an 
> image of the problem?
>
> Ben Root
>
Please find attached a picture of the problem. How is it possible to 
solve the problems?

This is the code:
from pylab import *
import matplotlib.pyplot as plt

x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 
20, 21, 22, 23, 24, 25, 26, 27, 28, 29]
y1 = [20, 24, 8, 4, 12, 22, 31, 25, 15, 28, 12, 27, 22, 22, 27, 14, 32, 
28, 8, 17, 2, 8, 29, 13, 14, 20, 11, 28, 8]
y2= [2, 32, 28, 1, 22, 11, 14, 27, 3, 31, 12, 20, 32, 24, 24, 16, 7, 10, 
12, 11, 3, 32, 10, 20, 14, 14, 3, 25, 14]
point_labels1 = ['A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 
'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 
'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1', 'A=1']
point_labels2 = ['B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 
'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 
'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1', 'B=1']

fig = plt.figure()
ax = fig.add_subplot(111)

ax.set_title('The red point should be on the path')

plt.plot(x, y1, 'bo', x, y2, 'go')
ax.grid(True)

maxy = max(max(y1), max(y2))
maxx = max(x)

ax.set_xlim((0.0, maxx))
ax.set_ylim((0.0, maxy))

# rotates and right aligns the x labels, and moves the bottom of the
# axes up to make room for them
fig.autofmt_xdate()

plt.xticks(range(0, maxx, 1))

plt.yticks(range(0, maxy, 1))
plt.xlabel('Longitude')
plt.ylabel('Latitude')
plt.legend(('Model length', 'Data length'),
           'best', shadow=True, fancybox=True)

for i, label in enumerate(y1):
   plt.text (x[i], y1[i]+0.2, label,
             horizontalalignment='center' )

for i, label in enumerate(y2):
   plt.text (x[i], y2[i]+0.2, label,
             horizontalalignment='center' )

plt.savefig('test.png')
plt.show()


Thank you in advance.

Hi,

Is there a way to prevent the matplotlib install from trying to compile for ppc for the c++ compiler? I usually set

export MACOSX_DEPLOYMENT_TARGET=10.6
export CFLAGS="-arch i386 -arch x86_64"
export CPPFLAGS="-arch i386 -arch x86_64"
export FFLAGS="-arch i386 -arch x86_64"
export LDFLAGS="-Wall -undefined dynamic_lookup -bundle -arch i386 -arch x86_64"

before installing packages, and make.osx has:

MACOSX_DEPLOYMENT_TARGET=10.6
OSX_SDK_VER=10.6
ARCH_FLAGS="-arch i386-arch x86_64"

All the gcc commands look like

gcc-4.0 -DNDEBUG -g -O3 -arch i386 -arch x86_64 [...] -isysroot /Developer/SDKs/MacOSX10.6.sdk [...]

but the c++ commands look like

c++ -arch ppc -arch i386 -isysroot /Developer/SDKs/MacOSX10.4u.sdk [...] -arch i386 -arch x86_64 -L/Users/tom/install/tmp/lib -syslibroot,/Developer/SDKs/MacOSX10.6.sdk -arch i386 -arch x86_64 [...]

which leads to an error when compiling _tkagg.so:

ld: in /Users/tom/install/tmp/lib/libz.1.dylib, missing required architecture ppc in file for architecture ppc
collect2: ld returned 1 exit status

If I try removing "-arch ppc -arch i386 -isysroot /Developer/SDKs/MacOSX10.4u.sdk" from the compile command, _tkagg.so compiles fine.

Any ideas?

Thanks!

Tom

On Fri, Sep 3, 2010 at 11:04 PM, karianne <kar...@as...> wrote:
> Hi,
>
> I am plotting several different symbols using 3 different colours. The
> colours indicate different data sets, whereas the symbols need not be
> explained. I would therefore like each label to have a different colour,
> i.e. each line in my legend should be written in a different colour
> specified. The legend is getting too long if I have to indicate what each
> symbol represents, plus it would be a repetition of the 3 data sets in
> question. How can I change the colour of the text in the legend?

Do something like

l1, = plot([1,2,3])
leg = legend([l1], ["Test"])

leg_texts = leg.get_texts() # list of matplotlib Text instances.
leg_texts[0].set_color("b")


>
> Second, how can I change the marker in the legend? I am plotting using
> errorbar(), but the marker shows up as a dot, and I would like it to show up
> as a '+', without having to change the actual dots in the plot.

I think it is best to use a proxy artist.

http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist

For example,


col, leg = "b", "test"
errorbar([1,2,3], [1,2,1],xerr=[0.1, 0.1, 0.1], yerr=[0.1, 0.1, 0.1],
         fmt='.',color=col)
l2, = plot([],[], "+", color=col)
l2.remove() # remove from the axes

legend([l2], [leg])


IHTH,

-JJ

ps. A code snippet, that cannot be run standalone, is not very useful.
If you do not want to post your own data, use some fake data.