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From: Shahar Shani-K. <ka...@po...> - 2014-07-06 10:52:30
|
Hi,
add linewidths=0 (or edgecolor='none', will do the same) to p = PatchCollection(patches, cmap=my_cmap)
note that PatchCollections can either get their properties from the original patch you create (the wedge) via the option *match_original* which defaults to false.
Shahar
On Jul 5, 2014, at 6:27 PM, Virgil Stokes <vs...@it...> wrote:
> I am using matplotlib version 1.3.1 with numpy 1.7.1 on a win32 platform for the
> following code:
>
>
> import matplotlib
> import matplotlib.pyplot as plt
> from matplotlib.collections import PatchCollection
> import matplotlib.colors as col
> import matplotlib.cm as cm
> from matplotlib.patches import Wedge
> import numpy as np
>
>
> def register_cmap(cmapName):
> """
> Purpose: define colormap using the from_List() method as a
> segmented list and register it.
> """
> startcolor = '#00AF33' # truegreen
> midcolor = '#FFE600' # yolk (a medium dark yellow)
> endcolor = '#FF0033' # bright red
> cmap2 = col.LinearSegmentedColormap.from_list(cmapName,
> [startcolor,midcolor,endcolor])
> cm.register_cmap(cmap=cmap2)
> return cmap2
>
> # Define my colormap red->yellow->green for curvature
> my_cmap = register_cmap('reylgr')
>
>
> # Modified matplotlib gallery example
> radii = np.arange(0.0,1.05,.05) # inner radius of rings
> width = 0.05 # width of rings
> patches = []
> for r in radii:
> wedge = Wedge((0.0,0.0), r+width, 0.0,360.0, width = width)
> patches.append(wedge)
>
> fig = plt.figure()
> ax = fig.add_subplot(111)
>
> colors = radii
> p = PatchCollection(patches, cmap=my_cmap)
> p.set_array(colors)
> ax.add_collection(p)
> ax.set_xlim(-1.5,+1.5)
> ax.set_ylim(-1.5,+1.5)
> plt.colorbar(p)
>
> plt.show()
>
> When I execute this code I do get concentric circles (wedge rings) as expected.
> However,
> I do not want "edges" along the boundaries of the rings. I would like the color
> changes
> between rings to look like the colorbar.
>
> I have tried several options with Wedge (e.g. edgecolor = "none"); but, this had
> no observable effect.
>
> Help on this would be appreciated.
>
>
>
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