php-java-bridge-users Mailing List for PHP/Java Bridge

Your suggested solution worked after I put quotes around my numeric
parameter -- the BigInteger constructor doesn't take Longs, but it does
take Strings!

$docRef->setVersion(new java("java.lang.BigInteger","1"));

Thanks for your help,
--Jon


-----Original Message-----
From: Jost Boekemeier [mailto:jos...@ya...]=20
Sent: Thursday, November 10, 2005 2:25 PM
To: Abbett, Jonathan; php...@li...
Subject: Ant: [Php-java-bridge-users] Bridge turns BigInteger into a
double?

Hi Jonathan,

please always create a java value explicitly instead
of relying on auto-conversions for php values[1]:

Instead of

  $obj->method($phpVal);

use

  $obj->method(new java("<param-class>", $phpVal));


So your example would read:

  $docRef->setVersion(new java("java.lang.BigInteger",
1));


> It looks like the PHP-Java Bridge is transforming my
> BigInteger=20

When possible a java value is represented as a php
value. "Possible" means: All sub-types of
java.lang.Number are represented as a php exact or
inexact number and all java strings are represented as
a UTF-8 encoded[2] php string.  Everything else is
represented as a opaque object handle.

To create an object handle for such a php value one
has to invoke the constructor as shown above.


Regards,
Jost Boekemeier

[1] all instances of java.lang.Number and all
instances of java.lang.String

[2] encoding can be changed with e.g.: java_set_file_encoding("ASCII").


=09

=09
	=09
___________________________________________________________=20
Gesendet von Yahoo! Mail - Jetzt mit 1GB Speicher kostenlos - Hier
anmelden: http://mail.yahoo.de

Hi Jonathan,

please always create a java value explicitly instead
of relying on auto-conversions for php values[1]:

Instead of

  $obj->method($phpVal);

use

  $obj->method(new java("<param-class>", $phpVal));


So your example would read:

  $docRef->setVersion(new java("java.lang.BigInteger",
1));


> It looks like the PHP-Java Bridge is transforming my
> BigInteger 

When possible a java value is represented as a php
value. "Possible" means: All sub-types of
java.lang.Number are represented as a php exact or
inexact number and all java strings are represented as
a UTF-8 encoded[2] php string.  Everything else is
represented as a opaque object handle.

To create an object handle for such a php value one
has to invoke the constructor as shown above.


Regards,
Jost Boekemeier

[1] all instances of java.lang.Number and all
instances of java.lang.String

[2] encoding can be changed with e.g.: java_set_file_encoding("ASCII").


	

	
		
___________________________________________________________ 
Gesendet von Yahoo! Mail - Jetzt mit 1GB Speicher kostenlos - Hier anmelden: http://mail.yahoo.de

I have a method that takes a BigInteger as input, but I can't seem to
get a BigInteger in there.  A code fragment:

=20

$docRef =3D $factory->createDocumentReferenceType();

$bigint =3D new java_class("java.math.BigInteger");

$docRef->setVersion($bigint->valueOf(1));

=20

I get an exception on that last line, which is reported in the PHP error
log:

=20

PHP Fatal error:  Uncaught [class java.lang.Exception:
java.lang.Exception: Invoke failed:
[org.chip.ping.xml.annotation.impl.DocumentReferenceTypeImpl@15b44d6]->s
etVersion(class java.lang.Double). Cause:
java.lang.IllegalArgumentException: argument type mismatch]

...

=20

It looks like the PHP-Java Bridge is transforming my BigInteger into a
java.lang.Double.  How do I prevent this from happening?  What
alternatives do I have?

=20

Thanks,

Jon Abbett

=20

=20

=20

=20

Does anyone know how to create a java two-dimensional array
and set its value of each element in php-code?
Thanks for your attention and help.

For example: one-dimensional array
<?php
 $Array =3D new JavaClass("java.lang.reflect.Array");
$String =3D new JavaClass("java.lang.String");
$entries =3D $Array->newInstance($String, 3);
$entries[0] =3D"a";
$entries[1] =3D"b";
$entries[2] =3D"c";
?>