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From: <php...@li...> - 2008-01-21 11:56:05
|
Hi again,
I forgot to mention the procedure java_inspect ($ObjectOrType) and the log4j viewer chainsaw.
java_inspect() returns type name of the java object or type as well as its public constructors and
features.
If you have set the log level to 4 or above, you should see the comm. protocol and clear error
messages from the back end.
Regards,
Jost Boekemeier
Heute schon einen Blick in die Zukunft von E-Mails wagen? Versuchen Sie´s mit dem neuen Yahoo! Mail. www.yahoo.de/mail
|
|
From: <php...@li...> - 2008-01-21 09:16:12
|
Hi,
> $obj = new Java("parser.ParseNode);
> echo $pobj->printHello(); //printHello is a static
should print something to the debug log.
> //printTest is not a static function
If the method printTest cannot be called, it means that the defining class is static or it has a
non-public constructor, in which case the PHP/Java Bridge returns the type instead of an instance.
(This behaviour is for compatibility with other bridges, but the recommended way to access a type
is through the java() function, of course.)
Regards,
Jost Boekemeier
Heute schon einen Blick in die Zukunft von E-Mails wagen? Versuchen Sie´s mit dem neuen Yahoo! Mail. www.yahoo.de/mail
|
|
From: <php...@li...> - 2008-01-21 08:15:53
|
hello,erverybody
I am sorry, in my former letter, I did not describe my problem clearly! I will give more information.
My website is written in php script and I have to call some java fuctions(these functions is used to implement a complicated algorithms), so i have to user the php-java-bridge to connect php and java,but I find it is very difficult to debug my programme. When I forget to include some libs, the php page just display
nothing, this situation slow my speed of developing very much. I hope someone is so kindly to tell me some way to debug my programme.
I am a newer to begin programming with php_java_bridge(begin from last Monday). In the coding process, I encountered two problems:
1. I can't use new a object with the parameter .
for example:
it is ok: $obj = new Java("parser.ParseNode);
it is not ok $pobj = new Java("parser.ParseNode","/home/lvhl/apache/test/parseweb/bin/elong.htm","gb2312");
//class parser.ParseNode has a construct function : ParseNode(String str ,String encoding)
2. I can't call a non-static function fo parser.ParseNode
also use the same example:
it is ok :
$obj = new Java("parser.ParseNode);
echo $pobj->printHello(); //printHello is a static function of parser.ParseNode
it is not ok and output is nothing: echo $pobj->printTest(); //printTest is not a static function
of parser.ParseNode
define of the functions:
public static String printHello()
{
return "Hello World,dajiahao!";
}
public String printTest()
{
return "Hello,test!";
}
Is there anybody who is so kind to tell me why ? Thank you very much!
My develop environment:
OS: Fedora 8
web server :Apache/2.2.6 (Unix)
PHP: php5.2.4
java : javac 1.6.0_03 java version "1.7.0"
php-java-bridge: php-java-bridge-5.0.0
browser:firefox 2.0.0.11 and IE7
and the php-java-bridge as a moudle of apache, didn't use tomcat
2008-01-21
lvhl.tech
|
|
From: <php...@li...> - 2008-01-21 07:55:45
|
hello,erverybody
My website is written in php script and I have to call some java fuctions(these functions is used to implement a complicated algorithms), but I find it is very difficult to debug my programme. When I forget to include some libs, the php page just display
nothing, this situation slow my speed of developing very much. I hope someone is so kindly to tell me some way to debug my programme.
I am a newer to begin programming with php_java_bridge(begin from last Monday). In the coding process, I encountered two problems:
1. I can't use new a object with the parameter .
for example:
it is ok: $obj = new Java("parser.ParseNode);
it is not ok $pobj = new Java("parser.ParseNode","/home/lvhl/apache/test/parseweb/bin/elong.htm","gb2312");
//class parser.ParseNode has a construct function : ParseNode(String str ,String encoding)
2. I can't call a non-static function fo parser.ParseNode
also use the same example:
it is ok :
$obj = new Java("parser.ParseNode);
echo $pobj->printHello(); //printHello is a static function of parser.ParseNode
it is not ok: echo $pobj->printTest(); //printTest is not a static function of parser.ParseNode
Is there anybody who is so kind to tell me why ? Thank you very much!
2008-01-21
lvhl.tech
|