std::derived_from
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Defined in header
<concepts> |
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template< class Derived, class Base >
concept derived_from = |
(since C++20) | |
The concept derived_from<Derived, Base> is satisfied if and only if Base is a class type that is either Derived or a public and unambiguous base of Derived, ignoring cv-qualifiers.
Note that this behavior is different to std::is_base_of when Base is a private or protected base of Derived.
Example
#include <concepts> class A {}; class B: public A {}; class C: private A {}; int main() { // std::derived_from == true only for public inheritance or exact same class static_assert( std::derived_from<B, B> == true ); // same class: true static_assert( std::derived_from<int, int> == false ); // same primitive type: false static_assert( std::derived_from<B, A> == true ); // public inheritance: true static_assert( std::derived_from<C, A> == false ); // private inheritance: false // std::is_base_of == true also for private inheritance static_assert( std::is_base_of_v<B, B> == true ); // same class: true static_assert( std::is_base_of_v<int, int> == false ); // same primitive type: false static_assert( std::is_base_of_v<A, B> == true ); // public inheritance: true static_assert( std::is_base_of_v<A, C> == true ); // private inheritance: true }
See also
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(C++11)
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checks if a type is derived from the other type (class template) |
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(C++11)(C++20)
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checks if a type can be converted to the other type (class template) |