std::move_iterator<Iter>::operator=

template< class U > move_iterator& operator=( const move_iterator<U>& other );		(until C++17)
template< class U > constexpr move_iterator& operator=( const move_iterator<U>& other );		(since C++17)

The underlying iterator is assigned the value of the underlying iterator of other, i.e. other.base().

The behavior is undefined if U is not convertible to Iter.	(until C++20)
This overload participates in overload resolution only if U is not the same type as Iter and std::convertible_to<const U&, Iter> and std::assignable_from<Iter&, const U&> are modeled.	(since C++20)

Parameters

other

-

iterator adaptor to assign

Return value

*this

Example

This section is incomplete Reason: no example

Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR	Applied to	Behavior as published	Correct behavior
LWG 3435	C++20	the converting assignment operator was not constrained	constrained

See also

(constructor) (C++11)

constructs a new iterator adaptor (public member function)