How to call setinterval in jQuery?

Question

I am trying to call setinterval function in jQuery, but it is giving error

Microsoft JScript runtime error: 'setinterval' is undefined

Here is my code

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <title></title>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js" type="text/javascript"></script>
    <script type="text/javascript">
        $(document).ready(function () {
            setInterval(function () {alert("HELLO WORLD!");}, 300);
        });
    </script>
</head>
<body>
//HTML code is here.
</body>
</html>

enter image description here

Works for me! jsfiddle.net/NsVGa (time changed so it can be easily stopped). — halfer
– halfer, Commented Apr 6, 2012 at 22:00
the code you shared is correct, I think we should see your whole code, if it's possible. — Okan Kocyigit
– Okan Kocyigit, Commented Apr 6, 2012 at 22:06
Is your script reference really src="//ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js"? If so, I think you need to prefix the URI with http:. — halfer
– halfer, Commented Apr 6, 2012 at 22:18
@halfer: Using a protocol-less URL works fine as long as you're not loading the page from a file:/// URL (in which case the protocol-less URL tries to load jQuery from that path locally instead of from the Google CDN). For more info: encosia.com/… — Dave Ward
– Dave Ward, Commented Apr 6, 2012 at 22:47
Are you cached with a bad version of the file. Clear the cache. — epascarello
– epascarello, Commented Apr 6, 2012 at 23:08

Cyrille Ka · Accepted Answer · 2012-04-06 22:42:18Z

4

The screenshot shows that you are trying to use "setinterval", that is without the capital "i", which is a mistake (javascript is case-sensitive). Either it is not the exact code you are using, either there is another piece of code somewhere who does call it.

answered Apr 6, 2012 at 22:42

Cyrille Ka

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1 Comment

Amit Over a year ago

It is EXACT code I am using and it is working fine in Firefox. If "i" is the issue then it should not run in Firefox.

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