django - access GET variable from urls.py

Question

I'm implementing django-haystack for the first time and need to make a geo-spatial search. Is it possible to access user inputs from urls.py?

I followed the haystack documentation and was able to do basic search using

from django.conf.urls.defaults import *
from haystack.forms import ModelSearchForm, HighlightedSearchForm
from haystack.query import SearchQuerySet
from haystack.views import SearchView
from haystack.views import SearchView, search_view_factory

**sqs = SearchQuerySet().all()**

urlpatterns = patterns('haystack.views',
url(r'^$', search_view_factory(
    view_class=SearchView,
    template='search/search.html',
    searchqueryset=sqs,
    form_class=HighlightedSearchForm
    ), name='haystack_search'),
)

I would need to do sqs = SearchQuerySet().dwithin('location', user_location, D(mi=5))

where user_location will be an user input and going to be passed through GET variable, is there any way I can access that here?

Thank you.

Community · Accepted Answer · 2017-05-23 12:04:51Z

1

Check How to access HttpRequest from urls.py in Django

Then your code looks like

urlpatterns = patterns('haystack.views',
url(r'^$', lambda request, *args, **kwargs: search_view_factory(
    view_class=SearchView,
    template='search/search.html',
    searchqueryset=SearchQuerySet().dwithin('location', request.GET.get('user_location'), D(mi=5)),
    form_class=HighlightedSearchForm
    ), name='haystack_search')(request, *args, **kwargs),
)

Normally its better to explicitly write a view to invoke corresponding search view.

edited May 23, 2017 at 12:04

CommunityBot

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answered May 6, 2012 at 8:34

okm

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1 Comment

Burhan Khalid Over a year ago

Normally its better to explicitly write a view to invoke corresponding search view. - yes, do not turn urls.py into psuedo-view controller.

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