How to list only files and not directories of a directory Bash?

ls -p | grep -v /

ls -p lets you show / after the folder name, which acts as a tag for you to remove.

• carlpett's find-based answer (find . -maxdepth 1 -type f) works in principle, but is not quite the same as using ls: you get a potentially unsorted list of filenames all prefixed with ./, and you lose the ability to apply ls's many options;
  also find invariably finds hidden items too, whereas ls' behavior depends on the presence or absence of the -a or -A options.

  • An improvement, suggested by Alex Hall in a comment on the question is to combine shell globbing with find:

     find * -maxdepth 0 -type f  # find -L * ... includes symlinks to files
    

    • However, while this addresses the prefix problem and gives you alphabetically sorted output, you still have neither (inline) control over inclusion of hidden items nor access to ls's many other sorting / output-format options.

• Hans Roggeman's ls + grep answer is pragmatic, but locks you into using long (-l) output format.

To address these limitations I wrote the fls (filtering ls) utility,

• a utility that provides the output flexibility of ls while also providing type-filtering capability,
• simply by placing type-filtering characters such as f for files, d for directories, and l for symlinks before a list of ls arguments (run fls --help or fls --man to learn more).

Examples:

fls f        # list all files in current dir.
fls d -tA ~  #  list dirs. in home dir., including hidden ones, most recent first
fls f^l /usr/local/bin/c* # List matches that are files, but not (^) symlinks (l)

Installation

Supported platforms

• When installing from the npm registry: Linux and macOS
• When installing manually: any Unix-like platform with Bash

From the npm registry

^{Note: Even if you don't use Node.js, its package manager, npm, works across platforms and is easy to install; try
curl -L https://git.io/n-install | bash}

With Node.js installed, install as follows:

[sudo] npm install fls -g

Note:

• Whether you need sudo depends on how you installed Node.js / io.js and whether you've changed permissions later; if you get an EACCES error, try again with sudo.

• The -g ensures global installation and is needed to put fls in your system's $PATH.

Manual installation

• Download this bash script as fls.
• Make it executable with chmod +x fls.
• Move it or symlink it to a folder in your $PATH, such as /usr/local/bin (macOS) or /usr/bin (Linux).

Listing content of some directory, without subdirectories

I like using ls options, for sample:

• -l use a long listing format
• -t sort by modification time, newest first
• -r reverse order while sorting
• -F, --classify append indicator (one of */=>@|) to entries
• -h, --human-readable with -l and -s, print sizes like 1K 234M 2G etc...

Sometime --color and all others. (See ls --help)

Listing everything but folders

This will show files, symlinks, devices, pipe, sockets etc.

so

find /some/path -maxdepth 1 ! -type d

could be sorted by date easily:

find /some/path -maxdepth 1 ! -type d -exec ls -hltrF {} +

Listing files only:

or

find /some/path -maxdepth 1 -type f

sorted by size:

find /some/path -maxdepth 1 -type f -exec ls -lSF --color {} +

Prevent listing of hidden entries:

To not show hidden entries, where name begin by a dot, you could add ! -name '.*':

find /some/path -maxdepth 1 ! -type d ! -name '.*' -exec ls -hltrF {} +

Then

You could replace /some/path by . to list for current directory or .. for parent directory.

You can also use ls with grep or egrep and put it in your profile as an alias:

ls -l | egrep -v '^d'
ls -l | grep -v '^d'

find files: ls -l /home | grep "^-" | tr -s ' ' | cut -d ' ' -f 9

find directories: ls -l /home | grep "^d" | tr -s ' ' | cut -d ' ' -f 9

find links: ls -l /home | grep "^l" | tr -s ' ' | cut -d ' ' -f 9

tr -s ' ' turns the output into a space-delimited file the cut command says the delimiter is a space, and return the 9th field (always the filename/directory name/linkname).

I use this all the time!

You are welcome!

ls -l | grep '^-'

Looking just for the name, pipe to cut or awk.

ls -l | grep '^-' | awk '{print $9}'

ls -l | grep '^-' | cut -d " " -f 13

{ find . -maxdepth 1 -type f | xargs ls -1t | less; }

added xargs to make it works, and used -1 instead of -l to show only filenames without additional ls info

You can one of these:

echo *.* | cut -d ' ' -f 1- --output-delimiter=$'\n'
echo *.* | tr ' ' '\n'
echo *.* | sed 's/\s\+/\n/g'
ls -Ap | sort | grep -v /   

This method does not use external commands.

bash$ res=$( IFS=$'\n'; AA=(`compgen -d`); IFS='|'; eval compgen -f -X '@("${AA[*]}")' )

bash$ echo "$res"
. . .

to list only file names (and directories at final point) without folders and anything else (properties, sizes etc) I used:

  ls -aRp 

• a=all entries (not ignore entries start with ".")
• R=recursive (in all subfolders)
• p=append "/" indicator to directories (if you like to clean them later) eg. /temp/list/a1/ will be listed as /a1 only

if you like to compare file existence in two different places then apply this too but it sort all files and directories independently of folder structure.

  ls -aRp |  sort --dictionary-order  

# ls -l | grep -v '^d'  | awk '{print $9}'

This one works perfectly for me, producing one filename per line listing, short format

ls -p . | grep -v '/'

Just adding on to carlpett's answer. For a much useful view of the files, you could pipe the output to ls.

find . -maxdepth 1 -type f|ls -lt|less

Shows the most recently modified files in a list format, quite useful when you have downloaded a lot of files, and want to see a non-cluttered version of the recent ones.

"find '-maxdepth' " does not work with my old version of bash, therefore I use:

for f in $(ls) ; do if [ -f $f ] ; then echo $f ; fi ; done