how to select a particular field using a jquery

Question

my code is

<div id="fields">
<form id="question-form">  <input type="hidden" name="question-main" value="<?php echo mysql_prep($_GET['ques']);?>" /></form>

<a class="vote-up-off">up vote</a>

<span class="vote-count-post"><?php echo $row["upvotes"]+$row["downvotes"];?></span>

 <a class="vote-down-off" id="<?php echo mysql_prep($_GET['ques']);?>" >down vote</a>

 <a class="star-off" href="#">favorite</a>
</div>

and my jquery code is

$("document").ready(function(){
$(".vote-up-off").click(function(){
// here i want the id of form field and votecountpost field which is up and down to this field
})
})

the div field repeats again and again as the field present on database.So i want to get the particular field id using jquery and will perform some action using jquery. How to find this?

Thulasiram · Accepted Answer · 2012-06-20 07:34:22Z

2

        $("document").ready(function () {
            $('.vote-up-off').live('click', function () {
                var formId = $(this).parents('form').attr('id');
                var voteCountPost = $(this).next('.vote-count-post').attr('id');
            });
        });

for form u can add class="VoteForm". so that it take that form attribute id in parents('').

        $("document").ready(function () {
            $('.vote-up-off').live('click', function () {
                var formId = $(this).parents('form.VoteForm').attr('id');
                var voteCountPost = $(this).next('.vote-count-post').attr('id');
            });
        });

edited Jun 20, 2012 at 7:34

answered Jun 20, 2012 at 7:09

Thulasiram

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1 Comment

StaticVariable Over a year ago

it works...thanx for the help...is there any another way..excpt parent()..to go up or down..????

dotancohen · Accepted Answer · 2012-06-20 07:09:02Z

1

Each div needs its own id. If the divs are created in a PHP loop, you can do this by incrementing a variable:

$divNumber=1;
while ( $row = mysql_fetch_array($results) )
{
    echo '<div id="fields-'.$divNumber.'">';
    // echo div content here
    echo '</div>';
    ++$divNumber;
}

answered Jun 20, 2012 at 7:09

dotancohen

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Comments

Th0rndike · Accepted Answer · 2012-06-20 07:06:07Z

0

in this line:

$(".vote-up-off).click(function(){...

it should be:

$(".vote-up-off").click(function(){...

answered Jun 20, 2012 at 7:06

Th0rndike

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