Get a part of XML using XSLT transformation

Question

I am new to the XSL transformations. Where i am trying to extract a part of XML using XSLT.

The Source XML

<tree>
    <trunk>
        <branch>
            <leaves></leaves>
            <flowers></flowers>
            <fruits></fruits>
        </branch>
    </trunk>
</tree>

and i am expecting the following XML as output

<root>    
    <branch>
        <leaves></leaves>
        <flowers></flowers>
        <fruits></fruits>
    </branch>
</root>

Please provide the transformation, i have been doing some random stuff for long time.

Bert · Accepted Answer · 2012-07-20 18:43:30Z

5

  <xsl:template match="/tree/trunk/branch">
    <root>
      <xsl:copy-of select="."/>
    </root>
  </xsl:template>

answered Jul 20, 2012 at 18:43

Bert

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David W · Accepted Answer · 2012-07-20 18:43:24Z

2

Something like the following

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0" >

<xsl:template match="/*">
    <xsl:element name="root">
        <xsl:for-each  select="//branch">
            <xsl:element name="branch">
                <xsl:for-each select="*">
                    <xsl:copy-of select="."/>
                </xsl:for-each>
            </xsl:element>
        </xsl:for-each>
    </xsl:element>
</xsl:template>

answered Jul 20, 2012 at 18:43

David W

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