No output when using awk inside bash script

Question

My bash script is:

output=$(curl -s http://www.espncricinfo.com/england-v-south-africa-2012/engine/current/match/534225.html | sed -nr 's/.*<title>(.*?)<\/title>.*/\1/p')

score=echo"$output" | awk '{print $1}'
echo $score

The above script prints just a newline in my console whereas my required output is

$ curl -s http://www.espncricinfo.com/england-v-south-africa-2012/engine/current/match/534225.html | sed -nr 's/.*<title>(.*
?)<\/title>.*/\1/p' | awk '{print $1}'

SA

So, why am I not getting the output from my bash script whereas it works fine in terminal am I using echo"$output" in the wrong way.

tvm · Accepted Answer · 2012-07-21 08:21:48Z

2

#!/bin/bash

output=$(curl -s http://www.espncricinfo.com/england-v-south-africa-2012/engine/current/match/534225.html | sed -nr 's/.*<title>(.*?)<\/title>.*/\1/p')
score=$( echo "$output" | awk '{ print $1 }' )

echo "$score"

Score variable was probably empty, since your syntax was wrong.

answered Jul 21, 2012 at 8:21

tvm

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1 Comment

Michael Krelin - hacker Over a year ago

The syntax is not universally wrong, it just sets $score to echo$output and pipes the output of assignment (which is none) to awk ;-)

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