Writing a single byte to the serial port in .NET 4.0 in C# causes a
InvalidOperationException was unhandled by user code
Every time a byte is sent to the SerialPort.
How do I write a single byte to the serial port?
//Serial Init
//Full fledged constuctor
public NetCommManager(String portName, TransmissionType trans, String baud, String parity, String stopBits, String dataBits)
{
nc_baudRate = baud;
nc_parity = parity;
nc_stopBits = stopBits;
nc_dataBits = dataBits;
nc_portName = portName;
nc_transType = trans;
//now add an event handler
comPort.DataReceived += new SerialDataReceivedEventHandler(netComm_DataReceived);
}
Config:
_commManger = new NetCommManager(commPortNumber,
NetCommManager.TransmissionType.Text, "19200", "None", "One", "8");
The Byte to be written:
_commManager.WriteByte(Convert.ToByte( 0x7B));
And WriteByte function is:
public void WriteByte(byte data)
{
//change data to array
//byte[] dataArray = new byte[1];
var dataArray = new byte[] {data};
//dataArray[0] = data;
comPort.Write(dataArray, 0, 1); // <-- Exception is thrown here
}
The NetCommManager class is very much based on this example
comPort = new...portion :). Somehow Jeff E managed to figure it (+1 to the answer obviously). On commented out code - consider if it shows significantly different variant of code. I don't think it is case here - so I'd simply remove it.